合并两个（或更多）“分组依据”，如查询结果表

Question

我有一张这样的桌子：

name area timestamp  
aa   10   timestamp  
aa   12   timestamp  
aa   22   timestamp  
bb   11   timestamp  
bb   11   timestamp  
cc   11   timestamp  

我可以做到以下几点：

select name, sum(area) as sum1 from mytable where "condition1 based on timestamp" group by name;  
select name, sum(area) as sum2 from mytable where "condition2 based on timestamp" group by name;

但我真正需要的应该是这样的：

name sum1 sum2  
aa   444  555  
bb   666  777  
cc   111  222  

任何想法可以做什么？

Answer 1

使用条件聚合：

select name, 
       sum(area) filter (where condition1) as sum1, 
       sum(area) filter (where condition2) as sum2
group by name;