【发布时间】:2015-10-18 19:21:51
【问题描述】:
我有以下问题。这个想法是它让我知道groups 和随后的users 可以访问每个component_instance。我想知道是否有更好的方法来做到这一点,因为查询很慢,但是每次处理这个表时都有这些额外的列真的很方便:
SELECT component_instances.*,
GROUP_CONCAT(DISTINCT IF(permissions.view, groups.id, NULL)) AS view_group_ids,
GROUP_CONCAT(DISTINCT IF(permissions.edit, groups.id, NULL)) AS edit_group_ids,
GROUP_CONCAT(DISTINCT IF(permissions.view, users.id, NULL)) AS view_user_ids,
GROUP_CONCAT(DISTINCT IF(permissions.edit, users.id, NULL)) AS edit_user_ids
FROM `component_instances`
LEFT OUTER JOIN permissions ON permissions.component_instance_id = component_instances.id
LEFT OUTER JOIN groups ON groups.id = permissions.group_id
LEFT OUTER JOIN groups_users ON groups_users.group_id = groups.id
LEFT OUTER JOIN users ON users.id = groups_users.user_id
GROUP BY component_instances.id
ORDER BY (case when component_instances.ancestry is null then 0 else 1 end), component_instances.ancestry, position
权限表是这样的(对不起 Rails!):
create_table "permissions", :force => true do |t|
t.integer "component_instance_id"
t.integer "group_id"
t.boolean "view", :default => false
t.boolean "edit", :default => false
end
权限类型有edit和view。可以分配一个组或同时分配一个组。权限也是递归的,如果component_instance 上没有组权限,我们必须检查其祖先以找到第一个设置权限的位置(如果有)。这使得一个查询变得非常重要,因为我可以将此查询与ancestry gem 提供的选择逻辑(物化路径树)结合起来。
更新
我发现这个查询基准测试更快:
SELECT component_instances.*,
GROUP_CONCAT(DISTINCT view_groups.id) AS view_group_ids,
GROUP_CONCAT(DISTINCT edit_groups.id) AS edit_group_ids,
GROUP_CONCAT(DISTINCT view_users.id) AS view_user_ids,
GROUP_CONCAT(DISTINCT edit_users.id) AS edit_user_ids
FROM `component_instances`
LEFT OUTER JOIN permissions ON permissions.component_instance_id = component_instances.id
LEFT OUTER JOIN groups view_groups ON view_groups.id = permissions.group_id AND permissions.view = 1
LEFT OUTER JOIN groups edit_groups ON edit_groups.id = permissions.group_id AND permissions.edit = 1
LEFT OUTER JOIN groups_users view_groups_users ON view_groups_users.group_id = view_groups.id
LEFT OUTER JOIN groups_users edit_groups_users ON edit_groups_users.group_id = edit_groups.id
LEFT OUTER JOIN users view_users ON view_users.id = view_groups_users.user_id
LEFT OUTER JOIN users edit_users ON edit_users.id = edit_groups_users.user_id
GROUP BY component_instances.id
ORDER BY (case when component_instances.ancestry is null then 0 else 1 end), component_instances.ancestry, position
这是对上述查询和表 CREATE 语句的解释:
+----+-------------+---------------------+--------+-----------------------------------------------+--------------------------------------------+---------+--------------------------------------------+------+------------------------------------------------------+
| id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra |
+----+-------------+---------------------+--------+-----------------------------------------------+--------------------------------------------+---------+--------------------------------------------+------+------------------------------------------------------+
| 1 | SIMPLE | component_instances | ALL | PRIMARY,index_component_instances_on_ancestry | NULL | NULL | NULL | 119 | "Using temporary; Using filesort" |
| 1 | SIMPLE | permissions | ALL | NULL | NULL | NULL | NULL | 6 | "Using where; Using join buffer (Block Nested Loop)" |
| 1 | SIMPLE | view_groups | eq_ref | PRIMARY | PRIMARY | 4 | 05707d890df9347c.permissions.group_id | 1 | "Using where; Using index" |
| 1 | SIMPLE | edit_groups | eq_ref | PRIMARY | PRIMARY | 4 | 05707d890df9347c.permissions.group_id | 1 | "Using where; Using index" |
| 1 | SIMPLE | view_groups_users | ref | index_groups_users_on_group_id_and_user_id | index_groups_users_on_group_id_and_user_id | 5 | 05707d890df9347c.view_groups.id | 1 | "Using index" |
| 1 | SIMPLE | edit_groups_users | ref | index_groups_users_on_group_id_and_user_id | index_groups_users_on_group_id_and_user_id | 5 | 05707d890df9347c.edit_groups.id | 1 | "Using index" |
| 1 | SIMPLE | view_users | eq_ref | PRIMARY | PRIMARY | 4 | 05707d890df9347c.view_groups_users.user_id | 1 | "Using index" |
| 1 | SIMPLE | edit_users | eq_ref | PRIMARY | PRIMARY | 4 | 05707d890df9347c.edit_groups_users.user_id | 1 | "Using index" |
+----+-------------+---------------------+--------+-----------------------------------------------+--------------------------------------------+---------+--------------------------------------------+------+------------------------------------------------------+
CREATE TABLE `component_instances` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`visible` int(11) DEFAULT '1',
`instance_id` int(11) DEFAULT NULL,
`deleted_on` date DEFAULT NULL,
`instance_type` varchar(255) DEFAULT NULL,
`component_id` int(11) DEFAULT NULL,
`deleted_root_item` int(11) DEFAULT NULL,
`locked_until` datetime DEFAULT NULL,
`theme_id` int(11) DEFAULT NULL,
`position` int(11) DEFAULT NULL,
`ancestry` varchar(255) DEFAULT NULL,
`ancestry_depth` int(11) DEFAULT '0',
`cached_name` varchar(255) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `index_component_instances_on_ancestry` (`ancestry`)
) ENGINE=InnoDB AUTO_INCREMENT=121 DEFAULT CHARSET=utf8
CREATE TABLE `groups` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL DEFAULT '',
PRIMARY KEY (`id`)
) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=utf8
CREATE TABLE `groups_users` (
`group_id` int(11) DEFAULT NULL,
`user_id` int(11) DEFAULT NULL,
KEY `index_groups_users_on_group_id_and_user_id` (`group_id`,`user_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8
CREATE TABLE `permissions` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`component_instance_id` int(11) DEFAULT NULL,
`group_id` int(11) DEFAULT NULL,
`view` tinyint(1) DEFAULT '0',
`edit` tinyint(1) DEFAULT '0',
PRIMARY KEY (`id`),
KEY `edit_permissions_index` (`edit`,`group_id`,`component_instance_id`),
KEY `view_permissions_index` (`view`,`group_id`,`component_instance_id`)
) ENGINE=InnoDB AUTO_INCREMENT=28 DEFAULT CHARSET=utf8
CREATE TABLE `users` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`real_name` varchar(255) DEFAULT NULL,
`username` varchar(255) NOT NULL DEFAULT '',
`email` varchar(255) NOT NULL DEFAULT '',
`crypted_password` varchar(255) DEFAULT NULL,
`administrator` int(11) NOT NULL DEFAULT '0',
`password_salt` varchar(255) DEFAULT NULL,
`remember_token_expires` datetime DEFAULT NULL,
`persistence_token` varchar(255) DEFAULT NULL,
`disabled` tinyint(1) DEFAULT NULL,
`time_zone` varchar(255) DEFAULT NULL,
`login_count` int(11) DEFAULT NULL,
`failed_login_count` int(11) DEFAULT NULL,
`last_request_at` datetime DEFAULT NULL,
`current_login_at` datetime DEFAULT NULL,
`last_login_at` datetime DEFAULT NULL,
`current_login_ip` varchar(255) DEFAULT NULL,
`last_login_ip` varchar(255) DEFAULT NULL,
`perishable_token` varchar(255) NOT NULL DEFAULT '',
PRIMARY KEY (`id`),
UNIQUE KEY `index_users_on_username` (`username`),
KEY `index_users_on_perishable_token` (`perishable_token`)
) ENGINE=InnoDB AUTO_INCREMENT=12 DEFAULT CHARSET=utf8
ORDER BY 来自 ancestry gem,但如果有更好的方法可以做到这一点,我很乐意将其作为拉取请求提交给他们。
【问题讨论】:
-
习惯上将所有文本保留在问题中,如果我是你,我会使用
UPDATE行分隔我的每个更新,并将词干全部保留在问题部分中。它使阅读更加清晰。 -
谢谢 Mehran,我已经更新了。我最初去回答我自己的问题,然后想到做一个赏金。
-
另外我认为如果使用第二个版本,您可以省略最后两个连接并在 group_concat 中使用 view_groups_users.user_id 和 edit_groups_users.user_id
-
大声笑,你说得对!我绝对可以摆脱用户表本身的加入。我会根据你的建议调查祖先排序的事情:)
标签: mysql ruby-on-rails group-by group-concat