Android JSON PHP 检查重复条目答案

【问题标题】：Android JSON PHP check for duplicate entryAndroid JSON PHP 检查重复条目
【发布时间】：2014-08-25 08:58:27
【问题描述】：

在我的 Android 应用程序中，我使用 JSON 将详细信息保存到服务器，并使用 PHP 文件。在我的 PHP 代码中，我想检查重复条目，现在在我的代码中不检查重复条目。我在下面给出我的代码，其中实体是用户的名字、中间名、姓氏、出生日期、出生月份、出生年份、电子邮件、手机号码和备用电子邮件。我需要检查重复的条目...例如，如果名字、姓氏和出生年份相同，则无需保存。

<?php


// array for JSON response
$response = array();

// check for required fields
if (isset($_POST['firstname']) && isset($_POST['middlename']) && isset($_POST['lastname']) && isset($_POST['dayb']) && isset($_POST['daym']) && isset($_POST['dayy']) && isset($_POST['mnumber']) && isset($_POST['pemail']) && isset($_POST['aemail'])) {

    $firstname = $_POST['firstname'];
    $middlename = $_POST['middlename'];
    $lastname = $_POST['lastname'];

    $dayb = $_POST['dayb'];
    $daym = $_POST['daym'];
    $dayy = $_POST['dayy'];

    $mnumber = $_POST['mnumber'];
    $pemail = $_POST['pemail'];
    $aemail = $_POST['aemail'];

    // include db connect class
    require_once __DIR__ . '/db_connect.php';

    // connecting to db
    $db = new DB_CONNECT();



    // mysql inserting a new row
    $result = mysql_query("INSERT INTO userentry(firstname,middlename, lastname,  dayb, daym, dayy, mnumber, pemail, aemail) VALUES('$firstname', '$middlename', '$lastname',  '$dayb', '$daym', '$dayy', '$mnumber', '$pemail', '$aemail')");

    // check if row inserted or not
    if ($result) {
        // successfully inserted into database
        $response["success"] = 1;
        $response["message"] = "Product successfully created.";

        // echoing JSON response
        echo json_encode($response);
    } else {
        // failed to insert row
        $response["success"] = 0;
        $response["message"] = "Oops! An error occurred.";

        // echoing JSON response
        echo json_encode($response);
    }
} 
else 
{
    // required field is missing
    $response["success"] = 0;
    $response["message"] = "Required field(s) is missing";

    // echoing JSON response
    echo json_encode($response);
}




?>

【问题讨论】：

标签： php json duplicates

【解决方案1】：

我不知道 PHP 语法，但你只需要更改插入查询

例子：-

INSERT INTO userentry (firstname,middlename, lastname,  dayb, daym, dayy, mnumber, pemail, aemail)  SELECT '$firstname', '$middlename', '$lastname',  '$dayb', '$daym', '$dayy', '$mnumber', '$pemail', '$aemail' WHERE NOT EXISTS  (SELECT aemail,mnumber   FROM tbl_responce    WHERE aemail = '$aemail' and mnumber   ='$mnumber')

【讨论】：

【解决方案2】：

我认为您需要进行查询以进行检查。在插入数据库之前尝试使用此查询。

SELECT * FROM your_table WHERE first_name = $_POST['firstname'] AND last_name = $_POST['firstname']

然后统计选中查询的数量。

if($result) {
    //there is a duplicate data in database. Do not insert
}
else{
  //insert your data here.
}

【讨论】：

【解决方案3】：

下面是对你来说应该可以正常工作的代码

$resp = mysql_fetch_assoc(mysql_query("SELECT count(*) as is_exist
                               FROM userentry
                               WHERE firstname='".$firstname."' and lastname='".$lastname."'
                                     and dayb='".$dayb."'" and daym='".$daym."'"
                                     and dayy='".$dayy."'"));

if($resp['is_exist']==0){
// Insert code
$result = mysql_query("INSERT INTO userentry(firstname,middlename, lastname,  dayb, daym, dayy, mnumber, pemail, aemail) VALUES('$firstname', '$middlename', '$lastname',  '$dayb', '$daym', '$dayy', '$mnumber', '$pemail', '$aemail')");
// check if row inserted or not
if ($result) {
    // successfully inserted into database
    $response["success"] = 1;
    $response["message"] = "Product successfully created.";

    // echoing JSON response
    echo json_encode($response);
} else {
    // failed to insert row
    $response["success"] = 0;
    $response["message"] = "Oops! An error occurred.";
    // echoing JSON response
    echo json_encode($response);
}
}else
{
//prompt that the record exist!
    $response["success"] = 0;
    $response["message"] = "Oops! User Already Exist";

    // echoing JSON response
    echo json_encode($response);
}

【讨论】：