【问题标题】:SQL:listing duplicate records from multiple join statements ?SQL:列出来自多个连接语句的重复记录?
【发布时间】:2018-09-03 05:15:08
【问题描述】:

你好 以下查询在加入多个表后返回所有员工

   select e.* 
    from dbo.EMP e
    join dbo.HREMP a 
      on a.ID    = e.ID
    join dbo.LOGO c
      on c.EMPID = e.id 
    join dbo.LOGOACC d
      on d.BADGENO = c.BADGENO  
     and d.ACCLVID in (2191, 2292, 2293, 2294, 2295, 2296, 2297)

共有 653 条记录返回

现在执行以下查询后

with EmployeeCTE as
(
   select e.* 
        from dbo.EMP e
        join dbo.HREMP a 
          on a.ID    = e.ID
        join dbo.LOGO c
          on c.EMPID = e.id 
        join dbo.LOGOACC d
          on d.BADGENO = c.BADGENO  
         and d.ACCLVID in (2191, 2292, 2293, 2294, 2295, 2296, 2297)
)
select k.id  from EmployeeCTE k
group  by ID
having count (k.id) >1

我发现有 135 条记录的计数大于 1。

如何列出所有计数超过一个的记录?

【问题讨论】:

    标签: sql sql-server join duplicates


    【解决方案1】:
    select * 
    from (select e.*  
               , count(*) over (partition by e.id) as cnt
            from dbo.EMP e
            join dbo.HREMP a 
              on a.ID    = e.ID
            join dbo.LOGO c
              on c.EMPID = e.id 
            join dbo.LOGOACC d
              on d.BADGENO = c.BADGENO  
             and d.ACCLVID in (2191, 2292, 2293, 2294, 2295, 2296, 2297) 
         ) tt 
    where tt.cnt > 1
    

    【讨论】:

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