PHP从对应的计数数组创建多维数组

Question

使用带有以下数据和嵌套循环的 PHP (7.1)，我试图让每个主机匹配 COUNTS 数组中的相应数字。

HOSTS:
Array ( 
  0 => 'example/search?results1'
  1 => 'thisone/search?results2'
  2 => 'thesetoo/search?results3'
)

COUNTS:
Array (
  0 => '3'
  1 => '5'
  2 => '7'
)

foreach ( $counts as $count ) {
  foreach ( $hosts as $host ) {
  $t = $count;
    for ($n=0; $n<$t; $n++) {
      $results[] = ++$host;
    }
  continue 2;
  }
}

echo 'THESE ARE ALL THE RESULTS:',PHP_EOL,PHP_EOL,var_dump($results);

我正在寻找的结果： 多维数组

Array (
0 => Array (
    0 => 'example/search?results1'
    1 => 'example/search?results1'
    2 => 'example/search?results1'
    )
1 => Array (
    0 => 'thisone/search?results2'
    1 => 'thisone/search?results2'
    2 => 'thisone/search?results2'
    3 => 'thisone/search?results2'
    4 => 'thisone/search?results2'
    )
2 => Array (
    0 => 'thesetoo/search?results3'
    1 => 'thesetoo/search?results3'
    2 => 'thesetoo/search?results3'
    3 => 'thesetoo/search?results3'
    4 => 'thesetoo/search?results3'
    5 => 'thesetoo/search?results3'
    6 => 'thesetoo/search?results3'
    )
)

注意每个 HOSTS 的结果数对应于 COUNTS 数组。

在上面的嵌套 for 循环中，我要么只为所有计数获取一个主机，要么为一维数组中的所有主机获取每个计数。我需要的是一个多维数组，但是嵌套的 for 循环逻辑正在逃避我。我已经尝试在循环中继续和中断，但没有运气。如果循环获得另一个计数，则它会跳过主机。如果它得到另一个主机，那么它会跳过计数。

主机或计数数组都没有模式。这些将始终相互对应，但它们将是随机字符串/数字。感谢您的帮助。

Answer 1

如果$hosts 和$counts 的计数等于：

$result = [];
foreach ($hosts as $i => $host) {
    $result[] = array_fill(0, $counts[$i], $host);
}

Answer 2

这个问题是array_map() 和array_fill() 的完美用法示例。

$hosts = array(
  0 => 'example/search?results1',
  1 => 'thisone/search?results2',
  2 => 'thesetoo/search?results3',
);

$counts = array(
  0 => '3',
  1 => '5',
  2 => '7',
);

$result = array_map(
    function($host, $count) {
        return array_fill(0, $count, $host);
    },
    $hosts,
    $counts
);

Answer 3

试试这个：

$hosts = array ( 
  0 => 'example/search?results1',
  1 => 'thisone/search?results2',
  2 => 'thesetoo/search?results3'
);

$counts = array (
  0 => '3',
  1 => '5',
  2 => '7'
);

$results =array();
foreach ( $counts as $count ) { 
    $key_of_count = array_search( $count, $counts ); 
    for ($i=0; $i < (int)$count; $i++) {
        $results[$key_of_count][] = $hosts[$key_of_count];
    }
}
echo "<pre>"; print_r($results); echo "</pre>";

Answer 4

如果您正在寻找仅使用循环而不使用任何花哨的数组函数的方法，那么这可能就是您正在寻找的答案：

$result = [];

foreach($counts as $k=>$count){
  $result[$k]='';
    for($i=0; $i < $count; $i++){
        $result[$k][] = $hosts[$k];
    }
}