在数组中添加它们的值时删除重复项[重复]

Question

假设我们有一个空字符串数组

const arr = [
  { value: 1, name: "king" },
  { value: 2, name: "master" },
  { value: 10, name: "lisa" },
  { value: 4, name: "lisa" },
  { value: 5, name: "jim" },
  { value: 6, name: "master" },
  { value: 1, name: "jim" },
  { value: 3, name: "" },
  { value: 2, name: "" },
]

我想删除重复的名称并将它们的值添加到同一个数组或另一个数组中。 期望的输出：

[
  { value: 1, name: "king" },
  { value: 8, name: "master" },
  { value: 14, name: "lisa" },
  { value: 6, name: "jim" },
  { value: 5, name: "" },
]

Answer 1

通过简单的循环检查重复，你可以减少数组。

arr = [
  { value: 1, name: "king" },
  { value: 2, name: "master" },
  { value: 10, name: "lisa" },
  { value: 4, name: "lisa" },
  { value: 5, name: "jim" },
  { value: 6, name: "master" },
  { value: 1, name: "jim" },
   { value: 3, name: "" },
  { value: 2, name: "" },
];
var a = new Set();

var array2 = [];
for (i = 0; i < arr.length; i++) {
 if(!a.has(arr[i].name)){
   array2.push(arr[i]);
   a.add(arr[i].name);
 }
 else{
   var name = arr[i].name;
   for (j = 0; j < array2.length; j++) {
      if(array2[j].name == name ){
        array2[j].value += arr[i].value;
      }
  }
  
 
}
}
console.log(array2);