使用 SQLite 插入返回 -1

Question

我已经为此苦苦挣扎了好几个小时。我的 SQLite 插入总是返回 -1 ...

这是我在一个文件中的主要活动的代码，它在另一个文件中调用我的数据库代码：

public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main);

    jobsdb = new NotifyJobsDBAdapter(this);
    jobsdb.open();

    currentjobid = 1;
    currentjob = new Job(currentjobid, "Starting Tele Num", "Starting Text Msg");
    currentjobid = jobsdb.insertJob(currentjob);
   // this last statement returns -1
}

这是我在另一个文件中的数据库适配器代码：

公共类 NotifyJobsDBAdapter {

private static final String DB_NAME = "notifyjobsdb";
private static final String DB_TABLE = "notifyjobs";
private static final int DB_VERSION = 1;
private final Context ctx;

// Database column names
private static final String JOB_ID = "jobid";
private static final String JOB_TELE = "contactnumber";
private static final String JOB_TEXT = "textmessage";

private SQLiteDatabase notifyjobsdb;
private NotifyJobsDatabaseHelper dbHelper;
private boolean openness;
private boolean err;
private boolean err0;
private int cnt;
private int i1;
private String s1;
private String s2;
private static String s3;
private int res;
private SQLiteException ex0;
private SQLiteException ex1;

private static class NotifyJobsDatabaseHelper extends SQLiteOpenHelper {

    private static final String DATABASE_CREATE = 
        "CREATE TABLE IF NOT EXISTS " + DB_TABLE +
        " (+ " + JOB_ID + "INTEGER PRIMARY KEY, " +
        JOB_TELE + "TEXT NOT NULL, " +
        JOB_TEXT + "TEXT NOT NULL);";

    private static final String DATABASE_UPGRADE = 
        "DROP TABLE IF EXISTS notifyjobs ";

    public NotifyJobsDatabaseHelper(Context _context) {
        super(_context, DB_NAME, null, DB_VERSION);
    }

    @Override
    public void onCreate(SQLiteDatabase db) {
        db.execSQL(DATABASE_CREATE);
    }

    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        db.execSQL(DATABASE_UPGRADE);
                }

}

public NotifyJobsDBAdapter(Context _context) {
    this.ctx = _context;
}

public void open() { 
    dbHelper = new NotifyJobsDatabaseHelper(ctx);
    try { notifyjobsdb = dbHelper.getWritableDatabase();
    } catch(SQLiteException ex) {
        ex0 = ex;
    }

}  

public void close() {
    notifyjobsdb.close();
}

//这是我的问题方法

public int insertJob(Job _job) {
    ContentValues newJobValues = new ContentValues();
    newJobValues.put(JOB_ID, _job.getjobid());
    newJobValues.put(JOB_TELE, _job.gettelenum());
    newJobValues.put(JOB_TEXT, _job.gettextmsg());
    notifyjobsdb.beginTransaction();
    // res is always returned a -1
    try {
    res = (int) notifyjobsdb.insertOrThrow(DB_TABLE, null, newJobValues);
    } catch (SQLiteException ex) {
        ex1 = ex;
    }

    notifyjobsdb.setTransactionSuccessful(); 
    close();
    return res;

这里，res 始终为 -1，调试器将 ex1 的详细信息显示为

"没有这样的表：notifyjobs:，编译时：INSERT INTO notifyjobs(contactnumber, textmessage, jobid) VALUES(?, ?, ?);

我将不胜感激！

Answer 1

必须将表的主要 id 字段命名为“_id”，以便 Android 知道在哪里绑定表的 id 字段。所以我建议你尝试将你的 ID 列命名为“_id”而不是“jobid”。

另外，我建议不要使用只执行一项操作的事务（您可以稍后决定将多个插入包装到一个事务中）。

Answer 2

1. 您的创建语句是错误的。这是正确的：

   private static final String DATABASE_CREATE = 
   "CREATE TABLE IF NOT EXISTS " + DB_TABLE +
   " (" + JOB_ID + " INTEGER PRIMARY KEY, " +
   JOB_TELE + " TEXT NOT NULL, " +
   JOB_TEXT + " TEXT NOT NULL);";
   

2. 如果您尝试插入与约束不匹配的行（例如，JOB_TELE/JOB_TEXT 列的主键或空值已存在），则会出现异常。

Answer 3

您的 DATABASE_CREATE 语句中有错误，因此您的表没有创建。这就是您收到错误消息的原因。尝试修复您的创建语句（打开括号后删除加号）：

private static final String DATABASE_CREATE = 
    "CREATE TABLE IF NOT EXISTS " + DB_TABLE +
    " (" + JOB_ID + " INTEGER PRIMARY KEY, " +
    JOB_TELE + " TEXT NOT NULL, " +
    JOB_TEXT + " TEXT NOT NULL);";