在 Python 中使用 Regex 在 Numeric Quantity 值之前和之后添加数量标识符

Question

我在 Python 中使用 Regex 在 Numeric Quantity 值之前和之后添加数量标识符。

基本上，我必须在数字数量之后添加 QtyOrd 和 Units 字样，它们不在文本中。

例如：

'PartNo-001A description 20 units some other description' => 'PartNo-001A description QtyOrd 20 units some other description'
'PartNo-001A description QtyOrd 20 some other description' => 'PartNo-001A description QtyOrd 20 units some other description'
'PartNo-001A description QtyOrd 20' => 'PartNo-001A description QtyOrd 20 units'
'PartNo-001A QtyOrd 20' => 'PartNo-001A QtyOrd 20 units'
'PartNo-001A 20 units'=> 'PartNo-001A QtyOrd 20 units'

正在使用的代码如下：

import re

def process_QtyOrd( text):
    for x in re.findall("(qtyord [0-9]+ units| [0-9]+ units|qtyord [0-9]+|qtyord[0-9]+units )", text.lower()):
        Text_Intermediate = "OrderQty " + str(re.search("[0-9]+", x).group()) + " Units"
    
    Text_Final = re.sub("(qtyord [0-9]+ units|[0-9]+ units|qtyord [0-9]+|qtyord [0-9]+ units)", Text_Intermediate, text, flags= re.IGNORECASE)

    return Text_Final

text1 = 'PartNo-001A description 20 units some other description'
text2 = '''
Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

QtyOrd 20 units some other description

''' 
text3 = 'PartNo-001A description QtyOrd 20 some other description'
text4 = 'PartNo-001A description QtyOrd 20'
text5 = 'PartNo-001A QtyOrd 20'
text6 = 'PartNo-001A 20 units'
text7 = ''' 

Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

QtyOrd 20 units some other description PartNo-001A
 
''' 

text8 = ''' 

Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

PartNo-001A

QtyOrd 
20

''' 

然后：

print(process_QtyOrd(text1))
print(process_QtyOrd(text2))
print(process_QtyOrd(text3))
print(process_QtyOrd(text4))
print(process_QtyOrd(text5))
print(process_QtyOrd(text6))
print(process_QtyOrd(text7))
print(process_QtyOrd(text8))

对于text8，代码不起作用。 你能帮我解决这个问题吗？

输出应该是这样的：

1. PartNo-001A description QtyOrd 20 Units some other description
 

2. Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

QtyOrd 20 Units some other description


3. PartNo-001A description QtyOrd 20 Units some other description
4. PartNo-001A description QtyOrd 20 Units
5. PartNo-001A QtyOrd 20 Units
6. PartNo-001A QtyOrd 20 Units
 

7. Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

QtyOrd 20 Units some other description PartNo-001A
 

8. Could you please redirect the ticket to the correct sales department so they can provide assistance and a quote for the items
below.

PartNo-001A

QtyOrd 
20
units

Answer 1

你可以使用

import re
text = r'PartNo-001A description 20 units some other description'
pattern = re.compile(r'\b(?:qtyord\s*(\d+)(?:\s*units)?|(\d+)\s*units)\b', re.I)
Text_Final = pattern.sub(r'QtyOrd \1\2 units', text)
print(Text_Final)
# => PartNo-001A description QtyOrd 20 units some other description

请参阅regex demo 和the Python demo。

详情：

• \b - 字边界
• (?: - 非捕获组的开始
  • qtyord
  • \s* - 零个或多个空格
  • (\d+) - 第 1 组（在替换模式中用 \1 表示）：一位或多位数字
  • (?:\s*units)? - 匹配零个或多个空格和 units 单词的可选组（如果您还想以单数形式匹配 unit，请在 s 之后添加 ?）
• | - 或
  • (\d+) - 第 2 组（在替换模式中用 \2 表示）：一位或多位数字
  • \s*units - 零个或多个空格和 units 单词（如果您还想匹配 unit 的单数，请在 s 之后添加 ?）
• ) - 小组结束
• \b - 字边界

Answer 2

假设您对 text8 的预期结果是 OrderQty 20 Units， 不是QtyOrd 20 units，请你试试：

def process_QtyOrd(text):
    m = re.match(r'^(.*?)(qtyord\s*\d+\s*units|\d+\s+units|qtyord\s+\d+)(.*)$', text, flags=re.IGNORECASE|re.DOTALL)
    if m:
        str= re.sub(r'\D*(\d+)\D*', r'OrderQty \1 Units', m.group(2))
        text = m.group(1) + str + m.group(3)
    return text

• re.match 将输入 text 分解为三个子字符串： 我们要修改的感兴趣的部分，前导子字符串，以及 尾随子字符串。
• 我使用\s 而不是 （空格）来匹配换行符。
• 感兴趣的部分由m.groups(2) 捕获。然后我们可以 用re.sub()函数修改它。
• 最后的text 是上述子字符串的串联。

[更新]

请您尝试以下方法：

def process_QtyOrd(text):
    text = re.sub(r'(qtyord\s*\d+\s*units|\d+\s+units|qtyord\s+\d+)', lambda m: re.sub(r'\D*(\d+)\D*', r'QtyOrd \1 Units', m.group(1)), text, flags=re.IGNORECASE|re.DOTALL)
    return text

现在，如果文本包含多个模式，它将起作用。我已将替换文本中的单词 OrderQty 更改为 QtyOrd。

• 我使用的不是上一个答案中的re.match() 函数 re.sub() 函数一次替换文本中所有出现的模式。
• 引入了 lambda 函数来评估替换部件作为 表达。

[更新2]

如果您想包含十进制数字，请尝试以下操作：

def process_QtyOrd(text):
    text = re.sub(r'(qtyord\s*\d+(?:\.\d+)?\s*units|\d+(?:\.\d+)?\s+units|qtyord\s+\d+(?:\.\d+)?)', lambda m: re.sub(r'\D*(\d+(?:\.\d+)?)\D*', r'QtyOrd \1 Units', m.group(1)), text, flags=re.IGNORECASE|re.DOTALL)
    return text

概念是将\d+ 替换为\d+(?:\.\d+)?，它匹配数字后跟可选的点和数字。