来自第二个表的 MySQL INNER JOIN (TOP10)

Question

$stmt = $conn->prepare('选择 a.*, c.*, SUM(a.money+b.RESULT) 作为结果
来自用户
    INNER JOIN 银行账户 c
        ON a.id = c.owner
    内部联接
    (
        选择所有者，总和（金额）作为结果
        从银行账户
        按所有者分组
    ) b ON a.id = b.owner
    ORDER BY ARESULT DESC LIMIT 10');

什么问题，它只显示错误的一条记录？我想列出最多 10 条记录 - 比如拥有 [money+(all his bankaccounts amount)] 的 TOP 10 最富有的人

假设.. 我有 2 张桌子。

表：用户

ID | username | money

1  | richman | 500

2  | richman2 | 600

表格：银行账户

ID | owner | amount

65 | 1     | 50

68 | 1     | 50

29 | 2     | 400

所以它会列出：

1. richman2 1000$

2. 富豪600美元

Answer 1

试试这个：

SELECT  a.*, (a.money + b.RESULT) AS ARESULT
FROM users a 
INNER JOIN (SELECT owner, SUM(amount) AS RESULT
            FROM bankaccounts
            GROUP BY owner
          ) b ON a.id = b.owner
ORDER BY ARESULT DESC 
LIMIT 10

Answer 2

尝试使用子查询...

$stmt = $conn->prepare('SELECT  a.*, 
    IFNULL((SELECT SUM(amount) FROM bankaccounts b WHERE b.owner=a.id),0) AS BANK_MONEY,
    (IFNULL(a.money,0) + IFNULL((SELECT SUM(amount) FROM bankaccounts c WHERE c.owner=a.id),0)) AS ARESULT
    FROM users a 
    ORDER BY ARESULT DESC LIMIT 0, 10');

编辑：为银行账户总额添加了一个字段

EDIT2：在 SQL 语句中添加 IFNULL，以防用户不在 BankAccounts 表中