【发布时间】:2020-06-14 16:40:00
【问题描述】:
我正在使用 android studio 和 SQLite。我在 SQLite 中设置了我的处方表,并为我的开始日期和结束日期使用了 TEXT 类型。在查询此数据时,我不太确定 TEXT 是否是合适的数据类型。我想显示开始日期早于或等于当前日期且结束日期大于或等于当前日期的记录。下面的代码来自我的 DatabaseHelper.java 类;
//Create prescription table
public static final String TABLE_PRESCRIPTION = "prescription_table";
public static final String COL_PRESCRIPTION_ID = "PRESCRIPTIONID";
public static final String COL_PRESCRIPTION__PATIENTID = COL_PATIENT_PATIENTID;
public static final String COL_PRESCRIPTION__DATE = "DATE";
public static final String COL_PRESCRIPTION__DRUGNAME = "DRUGNAME";
public static final String COL_PRESCRIPTION__CONCENTRATION = "CONCENTRATION";
public static final String COL_PRESCRIPTION__DOSAGE = "DOSAGE";
public static final String COL_PRESCRIPTION__PREPARATION = "PREPARATION";
public static final String COL_PRESCRIPTION__STARTDATE = "STARTDATE";
public static final String COL_PRESCRIPTION__ENDDATE = "ENDDATE";
public static final String COL_PRESCRIPTION__DOCTORID = "DOCTORID";
public void onCreate (SQLiteDatabase db) {
String prescriptiontable = "CREATE TABLE " + TABLE_PRESCRIPTION + "(PRESCRIPTIONID INTEGER PRIMARY KEY AUTOINCREMENT, PATIENTID INTEGER, DATE TEXT, DRUGNAME TEXT, CONCENTRATION TEXT, DOSAGE TEXT, PREPARATION TEXT, STARTDATE TEXT, ENDDATE TEXT, DOCTORID INTEGER)";
//execute SQL statements
db.execSQL(prescriptiontable);
}
public Cursor getPrescriptionsPerPatient(String patientid){
SQLiteDatabase db = this.getReadableDatabase();
//SQL select statement
Cursor data = db.rawQuery("SELECT * FROM prescription_table WHERE PATIENTID =? AND strftime('%d/%m/%Y',date('now') BETWEEN " +
"STARTDATE AND ENDDATE)",
new String[]{patientid});
return data;
}
错误在 getPrescriptionsPerPatient() 方法中。任何帮助,将不胜感激!谢谢
【问题讨论】:
-
如果你想比较除相等之外的任何日期,你需要使用一种可以有意义地排序的格式,就像 sqlite 日期和时间函数所接受的格式。
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你还需要修复你的语法错误。
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@Shawn 哪个语法错误?
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@Niamh:
date('now')后缺少右括号
标签: android sqlite date sqldatatypes