【发布时间】:2021-11-04 15:00:14
【问题描述】:
我为 ag 网格创建了一个具有删除功能的单独组件。单击删除按钮时,删除方法接收到该单行数据,并且我能够进行删除调用。现在如何在删除后更新表?如果我可以从表中过滤掉已删除的行并将其发送回表,我在考虑而不是再次对后端进行 api 调用以再次获取数据。但是,由于我在一个单独的组件中,我没有整个表格数据而只有一行数据,我该怎么做呢?
HTML
<ag-grid-angular
#agGrid
style="width: 100%; height: 500px;"
class="ag-theme-alpine"
domLayout='autoHeight'
[rowData]="rowData"
[gridOptions]="gridOptions"
[frameworkComponents]="frameworkComponents"
>
</ag-grid-angular>
buttonRenderer 组件代码
public onDelete = async ($event) => {
if ((await this.teamService.deleteTeamMember(this.params.node.data._id)) === false)
{
return;
}
this.notification.success('Team member deleted successfully.');
//this.team = this.team.filter((item) => item._id !== customer._id);
};
网格组件
this.gridOptions = {
suppressMenuHide: false,
columnDefs: [
{ headerName: 'Name', field: 'fullName', width: 150, sortable: true, filter: true },
{ headerName: 'Email', field: 'email', width: 170, sortable: true, filter: true, tooltipField: 'email'},
{
suppressMovable: true,
headerName: 'Status',
width: 100,
field: 'disabled', cellRenderer: (params) =>
params.data.disabled === false ? `<img src="assets/images/check.svg">` : `<img src="assets/images/minus.svg">`
},
{
headerName: 'Last Login',
field: 'lastLoginDate',
sortable: true,
filter: true,
cellRenderer: (params) => params.data.lastLoginDate ?
new Date(params.data.lastLoginDate).toISOString().split('T')[0] +
`<img src="assets/images/clock.svg">` +
new Date(params.data.lastLoginDate).toISOString().split('T')[1] : ``
},
{
headerName: 'Created',
width: 130,
field: 'dateCreated',
cellRenderer: (params) => new Date(params.data.dateCreated).toISOString().split('T')[0],
sortable: true,
filter: true
},
{
cellRenderer: 'buttonRenderer',
cellRendererParams: {
onClick: this.onBtnClick1.bind(this),
label: 'Click 1'
}
},
],
}
【问题讨论】: