Twitter API 实现“趋势”

Question

我正在尝试使用 Twitter API 列出热门话题。在调用我的函数并分配给“X”（然后打印“X”）后，我返回（以 JSON 格式解析）如下所示：

puts X

{"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more info...
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}

我可以通过调用更接近我想要的输出

X.each do |T|
  puts T["trends"]
end

我可以让它像这样打印每一行：

{"name"=>"blah blah", "query" =>"blah blah" and a bunch more information
{"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
{"name"=>"blah3 blah3", and so on and so forth.}

如何让我的代码仅打印热门主题的名称？我在想这将是类似于

X.each do |T|
  puts T["trends"]["name"]
end

但这不起作用。我怎样才能让它只显示

blah  blah
blah2 blah2
blah3 blah3

根据迭戈 当我调用以下命令时，我得到了从字符串到整数的无转换错误。

X["trends"].each do |T|
    puts T["name"]
end

当我调用 X.inspect 时，我只会得到我放在问题顶部的内容，并在趋势周围添加了一组 []。

[{"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more info...
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}]

我想通了。

X.each do |trend|
    trend["trends"].each do |topic|
        puts topic["name"]
    end
end

Answer 1

你必须遍历'trends':

response = {"trends"=>[{"name"=>"blah blah", "query" =>"blah blah" and a bunch more information
            {"name"=>"blah2 blah2", "query"=>"blah blah" and a bunch more...
            {"name"=>"blah3 blah3", and so on and so forth.}]}

response['trends'].each do |trend|
  trend['name'] # do what you want with this
end

或者获取所有名字的数组：

response['trends'].map { |t| t['name'] }
# => ["blah blah", "blah2 blah2", "blah3 blah3"]