【发布时间】:2017-09-25 08:05:51
【问题描述】:
如何在 PHP 中获取这个 Java SHA1 结果?
// Generating the Signature - Java
// import java.security.MessageDigest;
// import org.apache.commons.codec.binary.Base64;
String userId;
String applicationKey; // E.g. "196087a1-e815-4bc4-8984-60d8d8a43f1d";
String applicationSecret; // E.g. "oYdgGRXoxEuJhGDY2KQ/HQ==";
long sequence; // fetch and increment last used sequence
String toSign = userId + applicationKey + sequence + applicationSecret;
MessageDigest messageDigest = MessageDigest.getInstance("SHA-1");
byte[] hash = messageDigest.digest(toSign.getBytes("UTF-8"));
String signature = Base64.encodeBase64String(hash).trim();
我需要 PHP 上的 UTF-8 Sha1,谢谢
这些代码输出的结果与 java utf-8 sha-1 不同:
1:
$toSign_base64 = trim(base64_encode($toSign));
$toSign_digest = trim(hash_hmac('sha1', base64_decode($toSign_base64), "", true));
$signature = trim(base64_encode($toSign_digest));
2:
$signature = trim(sha1($toSign));
3:
$signature = trim(base64_encode(sha1($toSign)));
结果:
"raw": "849165ca-7af7-4951-6969-e19fc9f50b66",
"java_utf8_sha1": "1kBtMaSGLLiUfoSh9qJaxQGZTiQ=",
"code_1": "07PGV/+gMgCylXyA2qPJ92y1eSo=",
"code_2": "d6406d31a4862cb8947e84a1f6a25ac501994e24",
"code_3": "ZDY0MDZkMzFhNDg2MmNiODk0N2U4NGExZjZhMjVhYzUwMTk5NGUyNA=="
【问题讨论】:
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您应该尝试自己编写代码。在doing more research 之后,如果您有问题发布您尝试过的方法,并清楚地解释什么不起作用,并提供a Minimal, Complete, and Verifiable example。阅读How to Ask 一个好问题。请务必take the tour 并阅读this。
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只使用 sha1() 有什么问题(当然,除了 SHA-1 不再被视为安全哈希)?
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我将它用于 Sinch 的后端身份验证,它使用 Java UTF-8 SHA-1
标签: java php encryption sha1 sinch