【发布时间】:2015-07-30 04:00:33
【问题描述】:
我需要创建一个字符串的符号。我在 PHP 中有一个工作代码:
function buildSign($toSign, $key) {
$signature = null;
$pkeyid = openssl_get_privatekey($key);
openssl_sign($toSign, $signature, $pkeyid);
openssl_free_key($pkeyid);
return base64_encode($signature);
}
如何在目标 c 中创建与此功能等效的函数?
我试过这段代码
- (NSString*) signString:(NSString*)string key:(NSString *)key {
const char *cKey = [key cStringUsingEncoding:NSUTF8StringEncoding];
const char *cData = [string cStringUsingEncoding:NSUTF8StringEncoding];
unsigned char cHMAC[CC_SHA1_DIGEST_LENGTH];
CCHmac(kCCHmacAlgSHA1, cKey, strlen(cKey), cData, strlen(cData), cHMAC);
NSData *hmac = [[NSData alloc] initWithBytes:cHMAC
length:sizeof(cHMAC)];
return [hmac base64EncodedString];
}
但它会返回一个非常短的字符串,如下所示:zM5GPdSiDooWSm78fLCdTnw1LHQ=。
我需要这样的长标志:
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
【问题讨论】:
标签: php objective-c encryption