【发布时间】:2016-05-08 10:45:55
【问题描述】:
我一直在为学校做一个附带项目,用户可以登录并记录他们拥有的志愿者小时数。我已经完成了连接到数据库并存储用户信息(包括加密密码)的注册页面。 我遇到的问题是用户尝试登录时。输入密码后,程序进入数据库并检索散列函数,但是当我尝试解密时,解密的行是空白的。我不确定为什么会这样,但想一些帮助解决这个问题。谢谢。
这是我的登录页面和 encrypt_decrypt() 函数的代码:
login.php 页面:
<?php
include("encrypt_decrypt.php");
$username="root";
$password="";
$server="localhost";
$db_name="userauthentication";
$uname="";
$pword="";
$error_msg = "";
if(isset($_POST["submit"])){
$db_handle = mysqli_connect($server, $username, $password);
$db_found = mysqli_select_db($db_handle, $db_name);
$uname = $_POST["uname"];
$uname = htmlspecialchars($uname);
$uname = mysqli_real_escape_string($db_handle, $uname);
$pword = $_POST["pword"];
$pword = htmlspecialchars($pword);
$pword = mysqli_real_escape_string($db_handle, $pword);
if($db_found){
if($uname == "admin"){
$SQL = "SELECT * FROM WHERE username = '$uname' AND pword = '$pword'";
$result = mysqli_query($db_handle, $SQL);
$num_rows = mysqli_num_rows($result);
if(isset($num_rows) && $num_rows > 0){
session_start();
$_SESSION['login'] = "2";
header("Location: adminpage.html");
}else{
print("error");
}
}else{
$SQL = "SELECT * FROM login WHERE username = '$uname'";
$result = mysqli_query($db_handle, $SQL);
$num_rows = mysqli_num_rows($result);
if($num_rows > 0){
$db_field = mysqli_fetch_assoc($result);
$pword_match = $db_field['password'];
$pword_match = encrypt_decrypt('decrypt', $pword_match);
print ($pword . "<br>");
print $pword_match;
if($pword == $pword_match){
session_start();
$_SESSION['login'] = "1";
header("Location: mainpage.html");
}else{
$error_msg = "<span class='error_msg'>Wrong password!</span>";
print $error_msg;
}
}else if($num_rows == 0){
$error_msg = "<span class='error_msg'>Wrong username!</span>";
print $error_msg;
}
}
}else{
$error_msg = "<span class='register'>Could not connect to database!</span>";
print $error_msg;
}
}
?>
这些是在 login.php 文件中给我带来麻烦的行:
$db_field = mysqli_fetch_assoc($result);
$pword_match = $db_field['password'];
$pword_match = encrypt_decrypt('decrypt', $pword_match);
print ($pword . "<br>");
print $pword_match;
我刚刚打印出这两行,这样我就可以看到发生了什么。 print $pword 行很好,但是 print $pword_match 给了我一个空白。
encrypt_decrypt() 函数:
<?php
function encrypt_decrypt($action, $string) {
$output = false;
$encrypt_method = "AES-256-CBC";
$secret_key = $string;
$secret_iv = "password";
// hash
$key = hash('sha256', $secret_key);
// iv - encrypt method AES-256-CBC expects 16 bytes - else you will get a warning
$iv = substr(hash('sha256', $secret_iv), 0, 16);
if( $action == 'encrypt' ) {
$output = openssl_encrypt($string, $encrypt_method, $key, 0, $iv);
$output = base64_encode($output);
}
else if( $action == 'decrypt' ){
$output = openssl_decrypt(base64_decode($string), $encrypt_method, $key, 0, $iv);
}
return $output;
}
?>
【问题讨论】:
-
制作两个函数。
-
密码应该永远被解密。使用单向哈希对密码进行哈希处理,使用 PHP 的密码哈希 API。
-
您永远不应该加密您的用户密码。您需要使用散列代替一些强大的散列,例如 PBKDF2、bcrypt、scrypt 和 Argon2。由于散列函数是单向函数,因此您将无法“解密”散列。为了验证您的用户,您可以再次通过哈希函数运行密码,以便与存储在数据库中的哈希值进行比较。查看更多:How to securely hash passwords?
标签: php mysql encryption login