Spring Data JPA 存储过程答案

【问题标题】：Spring Data JPA Stored ProcedureSpring Data JPA 存储过程
【发布时间】：2015-12-26 09:29:18
【问题描述】：

我正在尝试调用 Oracle 存储过程，下面是我的实体和存储库类

import javax.persistence.Column;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.NamedStoredProcedureQuery;
import javax.persistence.ParameterMode;
import javax.persistence.StoredProcedureParameter;

@NamedStoredProcedureQuery(name = "casedetails", procedureName = "APPS.GET_SR_DATA", resultClasses = Case.class, parameters = {
        @StoredProcedureParameter(name = "p_sr_number", mode = ParameterMode.IN, type = String.class),
        @StoredProcedureParameter(name = "p_results", mode = ParameterMode.REF_CURSOR, type = void.class),
        @StoredProcedureParameter(name = "p_retVal", mode = ParameterMode.OUT, type = Long.class),
        @StoredProcedureParameter(name = "p_errMsg", mode = ParameterMode.OUT, type = String.class) })
/* }) */
@Entity
public class Case implements Serializable {

    @Id
    @Column(name = "sr_number")
    private String caseNumber;
    @Column(name = "problem_summary")
    private String caseTitle;
    @Column(name = "sr_type")
    private String caseCategory;
}

我的存储库类，

import org.springframework.data.repository.query.Param;
import org.springframework.data.jpa.repository.JpaRepository;
import org.springframework.data.jpa.repository.query.Procedure;

public interface CaseRepository extends JpaRepository<Case,String>{

    @Procedure(name = "casedetails", procedureName = "APPS.GET_SR_DATA")
    List<Case> findByCaseNumber(@Param("caseNumber") String caseNumber);
}

下面是persistence.xml

<?xml version="1.0"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence persistence_1_0.xsd" version="1.0">

    <persistence-unit name="case-rest-service" transaction-type="RESOURCE_LOCAL">
        <provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
        <exclude-unlisted-classes>false</exclude-unlisted-classes>
    </persistence-unit>

</persistence>

项目 pom.xml 条目

<dependency>
            <groupId>org.springframework.hateoas</groupId>
            <artifactId>spring-hateoas</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.data</groupId>
            <artifactId>spring-data-jpa</artifactId>
        </dependency>
        <dependency>
            <groupId>org.springframework.data</groupId>
            <artifactId>spring-data-commons</artifactId>
        </dependency>
<dependency>
            <groupId>org.eclipse.persistence</groupId>
            <artifactId>eclipselink</artifactId>
            <version>2.6.0-M3</version>
        </dependency>

        <dependency>
            <groupId>org.hibernate</groupId>
            <artifactId>hibernate-validator</artifactId>
            <scope>runtime</scope>
        </dependency>
        <dependency>
            <groupId>org.hibernate</groupId>
            <artifactId>hibernate-entitymanager</artifactId>
        </dependency>

当我尝试运行存储库测试时，我看到以下错误，

Object of class [org.springframework.data.jpa.repository.query.PartTreeJpaQuery] must be an instance of class org.springframework.data.jpa.repository.query.StoredProcedureJpaQuery; nested exception is java.lang.IllegalArgumentException: Object of class [org.springframework.data.jpa.repository.query.PartTreeJpaQuery] must be an instance of class org.springframework.data.jpa.repository.query.StoredProcedureJpaQuery

我以前从未将 Spring Data JPA 与存储过程一起使用，但我很感激这里的任何反馈/输入

【问题讨论】：

你解决了吗？
有人知道如何解决这个问题吗？
@Procedure 注释也有同样的问题。

标签： spring-data-jpa

【解决方案1】：

我从来没有找到解决方案，所以用了不同的方法

@Repository 
public interface MyObjectRepository extends CrudRepository<MyObject, String>  {
    @Query(value = "EXECUTE [dbo].[myProc] :fieldName, :pages", nativeQuery = true)
    Set<MyObject> findAllByFieldName(@Param("fieldName") String fieldName, @Param("pages") int pages);
}

这是相似的，我建议了相同的答案question

此链接可能会有所帮助DATA REPOSITORIES IN SPRING DATA JPA

【讨论】：