Powershell SaveFileDialog - 弹出两次

Question

请告诉我为什么在这段代码中 SaveFileDialog() 会提示两次输入文件名。

Function output-scrub{
  [System.Reflection.Assembly]::LoadWithPartialName("System.windows.forms") | Out-Null

  $global:SaveFileDialogNB = New-Object System.Windows.Forms.SaveFileDialog
  $global:SaveFileDialogNB.initialDirectory = "\\server\folder"
  $global:SaveFileDialogNB.filter = "All files (*.*)| *.*"
  $global:SaveFileDialogNB.SupportMultiDottedExtensions = $true
  #$global:SaveFileDialogNB.ShowDialog() | Out-Null
  #just to display the filename value
  $global:SaveFileDialogNB.filename
  #get just filename and the extension into a variable
  #$F1Filename = Split-Path $global:OpenFileDialog.filename -Leaf  ---commented out, only here if we only want to show filename extension alone.
    $global:SaveFileDialogNB.ShowDialog() | Out-Null
    if($SaveFileDialogNB.ShowDialog() -eq 'OK'){
        convertToHashTWO
    }
  return
}


function outPutScrubbedBalances{
    output-scrub
    write-host "file has been saved"
    return
}

这让我发疯了。

Answer 1

您已致电$ShowDialog() 两次。一次在 if 语句之前，第二次在 if 语句的条件部分中与“OK”进行比较。

调用一次，捕获对话结果，然后检查结果：

$result = $yourDialog.ShowDialog()  
if($result  -eq "OK")               
{              
    # Do something
}

或者，只需在if 语句的条件部分调用它并检查结果：

if($yourDialog.ShowDialog() -eq "OK")
{
    # do something
}

---

旁注：处理一次性组件很重要，不要忽视它。显示对话框并确保在使用后处理它的更好方法是：

$dialog = New-Object System.Windows.Forms.SaveFileDialog
try
{
    #Set up dialog, for example
    $dialog.filter = "All files (*.*)| *.*"
    if($dialog.ShowDialog() -eq "OK")
    {
        # do something here, for example
        Write-Host "Save Clicked."
    }
}
finally
{
    if($dialog) { $dialog.Dispose() }
}