joomla php从高到低排序数组[重复]

Question

我正在尝试从高到低对数组进行排序。

查询是在 Joomla 模块中编写的，是这个：

$authors = array();
    if (count($rows))
    {
        foreach ($rows as $row)
        {
            $author = JFactory::getUser($row->created_by);
            $author->link = JRoute::_(K2HelperRoute::getUserRoute($author->id));

            $query = "SELECT id, gender, description, image, url, `group`, plugins FROM #__k2_users WHERE userID=".(int)$author->id;
            $db->setQuery($query);
            $author->profile = $db->loadObject();

            if ($params->get('authorAvatar'))
            {
                $author->avatar = K2HelperUtilities::getAvatar($author->id, $author->email, $componentParams->get('userImageWidth'));
            }

            if (K2_JVERSION != '15')
            {
                $languageCheck = '';
                if ($application->getLanguageFilter())
                {
                    $languageTag = JFactory::getLanguage()->getTag();
                    $languageCheck = "AND i.language IN (".$db->Quote($languageTag).", ".$db->Quote('*').") AND c.language IN (".$db->Quote($languageTag).", ".$db->Quote('*').")";
                }
                $query = "SELECT i.*, c.alias as categoryalias FROM #__k2_items as i
                LEFT JOIN #__k2_categories c ON c.id = i.catid
                WHERE i.created_by = ".(int)$author->id."
                AND i.published = 1
                AND i.access IN(".implode(',', $user->getAuthorisedViewLevels()).")
                AND ( i.publish_up = ".$db->Quote($nullDate)." OR i.publish_up <= ".$db->Quote($now)." )
                AND ( i.publish_down = ".$db->Quote($nullDate)." OR i.publish_down >= ".$db->Quote($now)." )
                AND i.trash = 0 AND created_by_alias='' AND c.published = 1 AND c.access IN(".implode(',', $user->getAuthorisedViewLevels()).") AND c.trash = 0 {$languageCheck} ORDER BY created DESC";
            }
            else
            {
                $query = "SELECT i.*, c.alias as categoryalias FROM #__k2_items as i
                LEFT JOIN #__k2_categories c ON c.id = i.catid
                WHERE i.created_by = ".(int)$author->id."
                AND i.published = 1
                AND i.access <= {$aid}
                AND ( i.publish_up = ".$db->Quote($nullDate)." OR i.publish_up <= ".$db->Quote($now)." )
                AND ( i.publish_down = ".$db->Quote($nullDate)." OR i.publish_down >= ".$db->Quote($now)." )
                AND i.trash = 0 AND created_by_alias='' AND c.published = 1 AND c.access <= {$aid} AND c.trash = 0 ORDER BY created DESC";
            }

            $db->setQuery($query, 0, 1);
            $author->latest = $db->loadObject();
            $author->latest->id = (int)$author->latest->id;
            $author->latest->link = urldecode(JRoute::_(K2HelperRoute::getItemRoute($author->latest->id.':'.urlencode($author->latest->alias), $author->latest->catid.':'.urlencode($author->latest->categoryalias))));

            $query = "SELECT COUNT(*) FROM #__k2_comments WHERE published=1 AND itemID={$author->latest->id}";
            $db->setQuery($query);
            $author->latest->numOfComments = $db->loadResult();

            if ($params->get('authorItemsCounter'))
            {
                if (K2_JVERSION != '15')
                {
                    $languageCheck = '';
                    if ($application->getLanguageFilter())
                    {
                        $languageTag = JFactory::getLanguage()->getTag();
                        $languageCheck = "AND language IN (".$db->Quote($languageTag).", ".$db->Quote('*').")";
                    }
                    $query = "SELECT COUNT(*) FROM #__k2_items  WHERE {$where} published=1 AND ( publish_up = ".$db->Quote($nullDate)." OR publish_up <= ".$db->Quote($now)." ) AND ( publish_down = ".$db->Quote($nullDate)." OR publish_down >= ".$db->Quote($now)." ) AND trash=0 AND access IN(".implode(',', $user->getAuthorisedViewLevels()).") AND created_by_alias='' AND created_by={$row->created_by} {$languageCheck} AND EXISTS (SELECT * FROM #__k2_categories WHERE id= #__k2_items.catid AND published=1 AND trash=0 AND access IN(".implode(',', $user->getAuthorisedViewLevels()).") {$languageCheck} )";
                }
                else
                {
                    $query = "SELECT COUNT(*) FROM #__k2_items  WHERE {$where} published=1 AND ( publish_up = ".$db->Quote($nullDate)." OR publish_up <= ".$db->Quote($now)." ) AND ( publish_down = ".$db->Quote($nullDate)." OR publish_down >= ".$db->Quote($now)." ) AND trash=0 AND access<={$aid} AND created_by_alias='' AND created_by={$row->created_by} AND EXISTS (SELECT * FROM #__k2_categories WHERE id= #__k2_items.catid AND published=1 AND trash=0 AND access<={$aid} ) ";
                }
                $db->setQuery($query);
                $numofitems = $db->loadResult();
                $author->items = $numofitems;
            }

            $authors[] = $author;

        }
    }


    return $authors;
}

然后将结果传递给这些变量，最后返回作者表。这张表我想从高到低排序。我已经尝试过 php 函数，但它们似乎都不起作用。

我无法确定查询是否检索到项目计数器之外的其他内容并将其设置为键。但是我已经尝试过诸如 arsort 之类的函数，它是按值而不是键排序的。

$db->setQuery($query);
$numofitems = $db->loadResult();
$author->items = $numofitems;
$authors[] = $author;
arsort($authors);

任何想法都值得赞赏

谢谢

Answer 1

一般数据库查询可以通过指定顺序来排序

$query->order('my_table.my_column desc')

如果您正在对 PHP 数组进行排序并且需要自定义排序条件，您可以将自己的排序条件与 usort 结合使用。例如：

// Your comparison function:

function myComparer($object1, $object2)
{
    if ($object1->item == $object2->item) {
       return 0;
    }

    return ($object1->item < $object2-item) ? -1 : 1;
}

// Sort the array in place

usort($authors, 'myComparer');

请注意，您可以通过简单地交换比较返回值来反转排序顺序：

return ($object1->itemCount < $object2-itemCount) ? 1 : -1;