【发布时间】:2016-12-29 00:09:34
【问题描述】:
[解决方案已添加到本文的编辑部分]
2 个动画子图垂直堆叠。
我想根据鼠标位置显示一条穿过它们的黑色垂直线。
到现在我也只能在移动鼠标的时候完全弄乱人形……
如何清除更新之间的旧垂直线?
(只是出于好奇:由于鼠标移动控制,我的 PC 粉丝即使不移动鼠标也执行代码时会发疯。鼠标有那么“计算昂贵”吗?!?)
import numpy as np
import matplotlib.pyplot as plt
import matplotlib.animation as animation
from time import sleep
val1 = np.zeros(100)
val2 = np.zeros(100)
level1 = 0.2
level2 = 0.5
fig, ax = plt.subplots()
ax1 = plt.subplot2grid((2,1),(0,0))
lineVal1, = ax1.plot(np.zeros(100))
ax1.set_ylim(-0.5, 1.5)
ax2 = plt.subplot2grid((2,1),(1,0))
lineVal2, = ax2.plot(np.zeros(100), color = "r")
ax2.set_ylim(-0.5, 1.5)
def onMouseMove(event):
ax1.axvline(x=event.xdata, color="k")
ax2.axvline(x=event.xdata, color="k")
def updateData():
global level1, val1
global level2, val2
clamp = lambda n, minn, maxn: max(min(maxn, n), minn)
level1 = clamp(level1 + (np.random.random()-.5)/20.0, 0.0, 1.0)
level2 = clamp(level2 + (np.random.random()-.5)/10.0, 0.0, 1.0)
# values are appended to the respective arrays which keep the last 100 readings
val1 = np.append(val1, level1)[-100:]
val2 = np.append(val2, level2)[-100:]
yield 1 # FuncAnimation expects an iterator
def visualize(i):
lineVal1.set_ydata(val1)
lineVal2.set_ydata(val2)
return lineVal1,lineVal2
fig.canvas.mpl_connect('motion_notify_event', onMouseMove)
ani = animation.FuncAnimation(fig, visualize, updateData, interval=50)
plt.show()
编辑1
由 Ophir 解决:
def onMouseMove(event):
ax1.lines = [ax1.lines[0]]
ax2.lines = [ax2.lines[0]]
ax1.axvline(x=event.xdata, color="k")
ax2.axvline(x=event.xdata, color="k")
编辑2
如果同一图中有更多数据集,例如:
ax1 = plt.subplot2grid((2,1),(0,0))
lineVal1, = ax1.plot(np.zeros(100))
lineVal2, = ax2.plot(np.zeros(100), color = "r")
ax1.set_ylim(-0.5, 1.5)
每个数据集的行都存储在ax1.lines[]:
-
ax1.lines[0]是lineVal1 -
ax1.lines[1]是lineVal2 -
ax1.lines[2]是你已经画过的垂直线。
这意味着onMouseMove 必须更改为:
def onMouseMove(event):
ax1.lines = ax1.lines[:2] # keep the first two lines
ax1.axvline(x=event.xdata, color="k") # then draw the vertical line
【问题讨论】:
标签: python matplotlib animation mouse-cursor