使用 Python 对 JSON 响应进行排序答案

【问题标题】：Sorting JSON response with Python使用 Python 对 JSON 响应进行排序
【发布时间】：2016-03-06 03:23:15
【问题描述】：

例如，需要帮助弄清楚如何按从大到小对 JSON 响应进行排序。以下是 JSON 响应的一部分：

{
"queue": "RANKED_SOLO_5x5",
"name": "Riven's Cutthroats",
"entries": [
  {
     "leaguePoints": 812,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 277,
     "playerOrTeamName": "CLG Bunso",
     "playerOrTeamId": "19732914",
     "wins": 356
  },
  {
     "leaguePoints": 567,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 56,
     "playerOrTeamName": "SKT Frost",
     "playerOrTeamId": "66401633",
     "wins": 160
  },
  {
     "leaguePoints": 751,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": true,
     "losses": 421,
     "playerOrTeamName": "C9 Hard",
     "playerOrTeamId": "47836799",
     "wins": 494
  },
  {
     "leaguePoints": 587,
     "isFreshBlood": false,
     "isHotStreak": true,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 157,
     "playerOrTeamName": "ShadowFiendv",
     "playerOrTeamId": "71181475",
     "wins": 265
  },
  {
     "leaguePoints": 1109,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": true,
     "losses": 353,
     "playerOrTeamName": "ApoIlo Price",
     "playerOrTeamId": "7250",
     "wins": 425
  },

现在，我已经获取了我需要的必要信息，如下所示：

def getChallengerLadder(region, APIKey):
    URL = "https://" + region + ".api.pvp.net/api/lol/" + region +     "/v2.5/league/challenger?type=RANKED_SOLO_5x5&api_key=" + APIKey
    print (URL)
    response = requests.get(URL)
    return response.json()


   responseJSON3 = getChallengerLadder(region, APIKey)
    x = 0
    while True:
        print (responseJSON3['entries'][x]['leaguePoints'], responseJSON3['entries'][x]['playerOrTeamName'] )
         x += 1

结果我得到一个列表如下（同样，下面只是一个小样本）：

608 Z Y Xydra
552 Silas Kroeger
1109 ApoIlo Price
601 Blem
587 Boy vs Girl
701 l am Bjerg
560 duo to homecomin

我想按从大到小对这个列表进行排序，但我不知道该怎么做。任何帮助将不胜感激！有没有比我已经完成的更好的方法？我假设您必须将响应放入数组中并对数组进行排序？还是有更好的方法？

【问题讨论】：

标签： python json sorting

【解决方案1】：

按leaguePoints排序

（我只使用json 模块来创建完整的工作示例）

text = '''{
"queue": "RANKED_SOLO_5x5",
"name": "Riven's Cutthroats",
"entries": [
  {
     "leaguePoints": 812,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 277,
     "playerOrTeamName": "CLG Bunso",
     "playerOrTeamId": "19732914",
     "wins": 356
  },
  {
     "leaguePoints": 567,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 56,
     "playerOrTeamName": "SKT Frost",
     "playerOrTeamId": "66401633",
     "wins": 160
  },
  {
     "leaguePoints": 751,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": true,
     "losses": 421,
     "playerOrTeamName": "C9 Hard",
     "playerOrTeamId": "47836799",
     "wins": 494
  },
  {
     "leaguePoints": 587,
     "isFreshBlood": false,
     "isHotStreak": true,
     "division": "I",
     "isInactive": false,
     "isVeteran": false,
     "losses": 157,
     "playerOrTeamName": "ShadowFiendv",
     "playerOrTeamId": "71181475",
     "wins": 265
  },
  {
     "leaguePoints": 1109,
     "isFreshBlood": false,
     "isHotStreak": false,
     "division": "I",
     "isInactive": false,
     "isVeteran": true,
     "losses": 353,
     "playerOrTeamName": "ApoIlo Price",
     "playerOrTeamId": "7250",
     "wins": 425
  }
]
}'''

import json

# simulate `getChallengerLadder`
responseJSON3 = json.loads(text)

result = sorted(responseJSON3['entries'], key=lambda x:x['leaguePoints'])

print result

【讨论】：

您好，谢谢您的回答。在您的示例中，您将“文本”设置为 JSON 响应的变量。如果我手头没有文字，我该怎么做？基本上，只有当我从 API 提示 JSON 时，文本才可用，并且每隔几分钟就会更改一次。例如，我不能做这样的事情：text = '''print (responseJSON3)'''' 因为那么 responseJSON3 被视为引号内的字符串？ S对不起，如果这看起来很简单，我只是在学习 Python
我只使用json.loads(text) 来模拟API 并获得类似于responseJSON3 的结果来创建工作示例。我在答案中将变量 j 更改为 responseJSON3。
print 在屏幕上发送文本，您不能将其分配给变量。您可以text = str(some_object)，但要获得正确的 JSON 文本，最好使用text = json.dumps(responseJSON3)。（但在我的示例中，您不必将 resonseJSON3 转换为文本）
谢谢，其实我上周就知道了，忘了再看你的回复，我使用了你的 sorted() 方法，将它分配给变量，然后打印了我需要的 2 个条目（leaguePoints 和 playerOrTeamName）