按字母顺序排序，然后是 NodeJS 中的符号

Question

按字母排序的最佳方法是什么，然后是 javascript/node 中的符号？我在下面使用此函数按字母顺序对其进行排序，但是“_text”在顶部排序。

const items = {
"objectb": "text",
"objecta": "one",
"_text": "two",
"objectc": "three"
}

const ordered = Object.keys(items).sort().reduce(
        (obj, key) => {
            obj[key] = items[key];
            return obj;
        }, {}
    );

// This produces the sorted object, however the symbol key is sorted at the top, whereas I would like it at the bottom.

RETURNS:
{
"_text": "text",
"objecta": "one",
"objectb": "two",
"objectc": "three"
}

WOULD LIKE:
{
"objecta": "one",
"objectb": "two",
"objectc": "three",
"_text": "text"
}

Answer 1

你可以先把字符串分成两个数组，分别排序，然后合并。如果存在任何其他符号，这将起作用。

const items = {
  objectb: "text",
  objecta: "one",
  _text: "two",
  objectc: "three",
};

const strComparator = (a, b) => {
  if (a < b) return -1;
  if (a > b) return 1;
  return 0;
};

const ordered = Object.keys(items).reduce(
    (acc, curr) => {
      if (/[a-z]/i.test(curr[0])) acc[0].push(curr);
      else acc[1].push(curr);
      return acc;
    },[[], []])
  .flatMap((arr) => arr.sort(strComparator))
  .reduce((obj, key) => {
    obj[key] = items[key];
    return obj;
  }, {});

console.log(ordered);

Answer 2

需要提供排序功能

var array = ['_', 'a', 'b']

array.sort(function(a, b) {
  // sort _ at the end
  if (a[0] == '_' && b[0] != '_') return 1;
  if (a[0] != '_' && b[0] == '_') return -1;
  // sort by standard string comparison
  return a.localeCompare(b);
})