按升序和降序对多个数组键进行排序，字符串与数字

Question

我有一个 JavaScript 对象数组：

这不是重复的问题。 因为，我有一个包含 2 个键（key、count）的对象数组。 我想排序，key 升序（即 字符串）和 value 降序（即 数字）。

 var array = [
  {"count":7,"key":"a"},
  {"count":10,"key":"b"},
  {"count":5,"key":"c"},
  {"count":10,"key":"a"},
  {"count":3,"key":"d"}
];

期望的输出：

     var array = [
      {"count":10,"key":"a"},
      {"count":10,"key":"b"},
      {"count":7,"key":"a"},
      {"count":5,"key":"c"},
      {"count":3,"key":"d"}
    ];

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => (b.count - a.count)));

key 排序为升序

count 排序为降序

我已经使用array.sort((a, b) => (b.count - a.count)) 方法进行排序计数。但是，无法弄清楚如何对对象的两个键进行排序。

Answer 1

您必须将逻辑|| 运算符 与localeCompare 函数结合使用。

|| 运算符仅在b.count - a.count 结果为零时才考虑第二个组件。

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => b.count - a.count || a.key.localeCompare(b.key)));

Answer 2

尝试关注

var array = [{"count":7,"key":"a"},{"count":10,"key":"b"},{"count":5,"key":"c"},{"count":10,"key":"a"},{"count":3,"key":"d"}];

console.log(array.sort((a, b) => {
  if(a.count === b.count) return a.key.localeCompare(b.key);
  return b.count - a.count;
}));