【发布时间】:2011-10-18 08:14:35
【问题描述】:
我想在安装完成后启动一个EXE,所以我写了一个自定义启动条件,如下所示:
[RunInstaller(true)]
public class InstallerClass : System.Configuration.Install.Installer
{
public InstallerClass() : base()
{
this.AfterInstall += new InstallEventHandler(InstallerClass_AfterInstall);
}
void InstallerClass_AfterInstall(object sender, InstallEventArgs e)
{
Directory.SetCurrentDirectory(
Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location));
ProcessStartInfo psi = new ProcessStartInfo(
Path.GetDirectoryName(
Assembly.GetExecutingAssembly().Location) + "\\MyApp.exe");
psi.WorkingDirectory = Path.GetDirectoryName(
Assembly.GetExecutingAssembly().Location);
psi.Verb = "runas";
Process p = new Process();
p.StartInfo = psi;
p.Start();
}
.
.
. }
问题:MyApp.exe 正在创建 http 请求以从服务器获取一些数据。如果 MyApp.exe 从此处启动,我每次都会收到 超时异常。如果我单独运行 MyApp.exe,它会成功创建 http 请求而不会超时。下面是http请求的代码:
HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(uri);
request.Timeout = TimeOut;
request.Credentials = CredentialCache.DefaultCredentials;
request.Proxy = WebRequest.DefaultWebProxy;
request.UseDefaultCredentials = true;
request.AllowAutoRedirect = true;
request.KeepAlive = false;
request.Method = "HEAD";
request.SendChunked = true;
using (HttpWebResponse response = (HttpWebResponse)request.GetResponse())
{
returnValue = response.StatusCode;
}
为什么会出现超时异常?我哪里做错了?
【问题讨论】:
标签: c# installation httpwebrequest timeout launch-condition