如何通过 PHP 获取 Google 索引页面计数

Question

您好，我正在尝试创建一个脚本，该脚本应该从 Google 检索所有索引页面的计数。只有总页数（来自 site:$domain 的结果）

我找到了这个脚本：

function getGoogleCount($domain) {
$content = file_get_contents('http://ajax.googleapis.com/ajax/services/search/web?v=1.0&filter=0&q=site:' . urlencode($domain));
$data = json_decode($content);
return intval($data->responseData->cursor->estimatedResultCount);
}

但是这个 API 是旧的并且给出了不同的计数，那么有没有其他方法来获取索引页面计数？

谢谢

Answer 1

试试这个：

<?php
function getpageindexed($name){
$weburl="http://ajax.googleapis.com/ajax/services/search/web?v=1.0&q=site:".$name."&filter=0";
$ch=curl_init();
curl_setopt($ch, CURLOPT_URL, $weburl);
curl_setopt($ch, CURLOPT_USERAGENT,$_SERVER['HTTP_USER_AGENT']);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt ($ch, CURLOPT_HEADER, 0);
curl_setopt ($ch, CURLOPT_NOBODY, 0);
curl_setopt($ch, CURLOPT_TIMEOUT, 30);
$json = curl_exec($ch);
curl_close($ch);
$data=json_decode($json,true);
if($data['responseStatus']==200)
return $data['responseData']['cursor']['resultCount'];
else
return false;
}

$name="domainname.com"; //your domain name
echo getpageindexed($name); //get indexed page
?>