我们没有开箱即用的任何东西,但我可以通过对SimpleMessageStore 进行小的修改来做你想做的事情。我已经发布了完整的RollingMessageStorein a gist。
底线是修改removeGroup 只删除第一条消息,而不是整个组。另外,将completeGroup 设为无操作。
设置expreGroupOnCompletion 以强制聚合器“删除”组(通过调用修改后的removeGroup() 方法。
这是SimpleMessageGroup 和RollingMessageGroup 之间的区别...
182,184c190,194
<
< groupUpperBound.release(groupIdToMessageGroup.get(groupId).size());
< groupIdToMessageGroup.remove(groupId);
---
> Message<?> message = this.groupIdToMessageGroup.get(groupId).getOne();
> if (message != null) {
> this.groupUpperBound.release(1);
> this.removeMessageFromGroup(groupId, message);
> }
(加上删除completeGroup()中的所有代码。
还有一个测试用例...
@Test
public void testRolling() {
AggregatingMessageHandler aggregator = new AggregatingMessageHandler(new MultiplyingProcessor(), new RollingMessageStore());
aggregator.setExpireGroupsUponCompletion(true);
aggregator.setReleaseStrategy(new ReleaseStrategy() {
@Override
public boolean canRelease(MessageGroup group) {
return group.size() == 3;
}
});
QueueChannel replyChannel = new QueueChannel();
Message<?> message1 = createMessage(3, "ABC", 3, 1, replyChannel, null);
Message<?> message2 = createMessage(5, "ABC", 3, 2, replyChannel, null);
Message<?> message3 = createMessage(7, "ABC", 3, 3, replyChannel, null);
Message<?> message4 = createMessage(9, "ABC", 3, 3, replyChannel, null);
Message<?> message5 = createMessage(11, "ABC", 3, 3, replyChannel, null);
aggregator.handleMessage(message1);
aggregator.handleMessage(message2);
aggregator.handleMessage(message3);
aggregator.handleMessage(message4);
aggregator.handleMessage(message5);
Message<?> reply = replyChannel.receive(10000);
assertNotNull(reply);
assertEquals(reply.getPayload(), 105);
reply = replyChannel.receive(10000);
assertNotNull(reply);
assertEquals(reply.getPayload(), 315);
reply = replyChannel.receive(10000);
assertNotNull(reply);
assertEquals(reply.getPayload(), 693);
}
请继续打开JIRA New Feature Issue,我们将考虑将此(或更通用的解决方案)添加到即将发布的 3.0 版本中。
使用correlation-strategy-expression="'foo'" 和
release-strategy-expression=size()==3.