【问题标题】:Link to an item on a paginated page in php链接到 php 中分页页面上的项目
【发布时间】:2011-08-27 00:56:56
【问题描述】:

我是 PHP / MySQL 方面的新手编码员。我目前正在开发一个网站,并为我在这个网站上遇到的一些问题找到了许多答案 - 很棒的资源! - 但现在我需要问我自己的一个我正在努力解决的问题。请多多包涵……

所以在我的网站上,我有一个侧面板,它显示来自数据库的推荐并随机提取 1 个结果,以便每次用户浏览网站时显示的推荐都会发生变化。侧面板是一个 php 包含并显示在整个站点中。我只展示了几行推荐信,然后包括了一个阅读更多链接。

在推荐页面上,我有 13 个推荐,每页 1 个(13 页)分页,因为每个推荐都很长 - 这就是客户想要的。

我要做的是从“阅读更多”链接链接到相关推荐 - 我认为最好使用 html 锚?我发现的问题是我似乎无法链接到其分页页面上的相关项目。如果我使用推荐 ID,我只能链接到 testimonials.php 的第 1 页,而不是链接到推荐出现的特定页面。我希望这是有道理的?

我在侧面板和推荐页面上包含了我的代码副本。

任何见解或帮助将不胜感激。

谢谢。

Sidebar.php

$gettest = mysql_query ("SELECT * FROM testimonial ORDER BY RAND() LIMIT 1");

while ($row=mysql_fetch_array($gettest)) 
{
$testimonial = $row['testimonial'];
$shorttest = myTruncate($testimonial, 200, " ");
?>

<blockquote><span class="bqstart">&#8220;</span><p><?PHP echo $shorttest;?></p><span class="bqend">&#8221;</span></blockquote>      
<p><a href="testimonials.php#<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>
<br clear='all' />

<?PHP
}                           
mysql_close($DB);
?>

Testimonials.php

<?php

include('connectDB.php'); 

$tableName="testimonial";
$targetpage = "testimonials.php";
$limit = 1; 

$query = "SELECT COUNT(*) as num FROM testimonial";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];

$stages = 3;
$page = mysql_escape_string($_GET['page']);
if($page){
$start = ($page - 1) * $limit;
}else{
$start = 0;
}   

// Get page data
$query1 = "SELECT * FROM testimonial LIMIT $start, $limit";
$result = mysql_query($query1);

// Initial page num setup
if ($page == 0){$page = 1;}
$prev = $page - 1;
$next = $page + 1;
$lastpage = ceil($total_pages/$limit);
$LastPagem1 = $lastpage - 1;                    

$paginate = '';
if($lastpage > 1)
{   

$paginate .= "<div class='paginate'>";
// Previous
if ($page > 1){
$paginate.= "<a href='$targetpage?page=$prev'>previous</a>";
}else{
$paginate.= "<span class='disabled'>previous</span>";   }

// Pages
if ($lastpage < 7 + ($stages * 2))  // Not enough pages to breaking it up
{
for ($counter = 1; $counter <= $lastpage; $counter++)
{
if ($counter == $page){
 $paginate.= "<span class='current'>$counter</span>";
}else{
 $paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}
elseif($lastpage > 5 + ($stages * 2))   // Enough pages to hide a few?
{

// Beginning only hide later pages
if($page < 1 + ($stages * 2))
{
for ($counter = 1; $counter < 4 + ($stages * 2); $counter++)
{
 if ($counter == $page){
     $paginate.= "<span class='current'>$counter</span>";
 }else{
     $paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}

// Middle hide some front and some back
elseif($lastpage - ($stages * 2) > $page && $page > ($stages * 2))
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $page - $stages; $counter <= $page + $stages; $counter++)
{
 if ($counter == $page){
     $paginate.= "<span class='current'>$counter</span>";
 }else{
     $paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
$paginate.= "...";
$paginate.= "<a href='$targetpage?page=$LastPagem1'>$LastPagem1</a>";
$paginate.= "<a href='$targetpage?page=$lastpage'>$lastpage</a>";
}

// End only hide early pages
else
{
$paginate.= "<a href='$targetpage?page=1'>1</a>";
$paginate.= "<a href='$targetpage?page=2'>2</a>";
$paginate.= "...";
for ($counter = $lastpage - (2 + ($stages * 2)); $counter <= $lastpage; $counter++)
{
 if ($counter == $page){
     $paginate.= "<span class='current'>$counter</span>";
 }else{
     $paginate.= "<a href='$targetpage?page=$counter'>$counter</a>";}
}
}           

}

// Next
if ($page < $counter - 1){
$paginate.= "<a href='$targetpage?page=$next'>next</a>";
}else{
$paginate.= "<span class='disabled'>next</span>";
}

$paginate.= "</div>";       

}
// pagination
echo $paginate;

?>



<?php 

while($row = mysql_fetch_array($result))
{



?>
<a name="<?PHP echo '' . $row["ID"] . '';?>"></a>

<blockquote><span class="bqstart">&#8220;</span><p><?PHP echo '' .nl2br($row["testimonial"]) . '';?></p><span class="bqend">&#8221;</span></blockquote> 
<p class="highlight"><?PHP echo '' . $row["name"] . '';?></p>
<br clear='all' />

<?PHP
}

echo $paginate;

mysql_close($DB);

?>

【问题讨论】:

  • 你能不能把页面 id 设置为'testimonial id'?这样,testimonials.php 页面只显示该 id 的推荐,您仍然可以在页面上进行分页。
  • 感谢 gmadd。关于如何做的任何指示?

标签: php hyperlink pagination anchor


【解决方案1】:

我不会详细介绍您可以对代码进行的所有更改,因为现在它很混乱。

您可能迷失在自己的代码中。

只需将这一行(在 sidebar.php 上)更改为:

<p><a href="testimonials.php?page=<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>

(类似于您在“Testimonials.php”页面上所做的。)

【讨论】:

  • 谢谢哈南。感谢反馈。正如我所说,我不是最好的编码员。想知道您是否可以指出代码有什么问题以及如何使它变得更好?谢谢
  • 没关系,我们都是从某个地方开始的。这没有错,但你可以更有效地做到这一点。尝试阅读有关类和对象的信息。它将使您的代码不那么拥挤。 :)
  • 非常感谢哈南。欣赏。
【解决方案2】:

像这样的:

<?php
$gettest = mysql_query ("SELECT * FROM testimonial ORDER BY RAND() LIMIT 1");

while ($row=mysql_fetch_array($gettest)) 
{
$testimonial = $row['testimonial'];
$shorttest = myTruncate($testimonial, 200, " ");
?>

<blockquote><span class="bqstart">&#8220;</span><p><?PHP echo $shorttest;?></p><span class="bqend">&#8221;</span></blockquote>      
<p><a href="testimonials.php?testimonialid=<?PHP echo '' . $row["id"] . '';?>"><?PHP echo '' . $row["name"] . '';?></a></p>
<br clear='all' />

<?PHP
}                           
mysql_close($DB);
?>

<?php
include('connectDB.php'); 

$query = "SELECT COUNT(*) as num FROM testimonial";
$total_pages = mysql_fetch_array(mysql_query($query));
$total_pages = $total_pages[num];

$testimonialid = mysql_escape_string($_GET['testimonialid']);  

// Get page data
$query1 = "SELECT * FROM testimonial WHERE id = ".$testimonialid;
$result = mysql_query($query1);

$paginate = '';
if($total_pages > $testimonialid)
{
    $paginate .= '<a href="testimonials.php?testimonialid='.($testimonialid+1).'">next</a>';
}
if($testimonialid > 1)
{
    $paginate .= '<a href="testimonials.php?testimonialid='.($testimonialid-1).'">previous</a>';
}
?>



<?php
echo $paginate;

while($row = mysql_fetch_array($result))
{
    ?>
    <a name="<?PHP echo '' . $row["ID"] . '';?>"></a>

    <blockquote><span class="bqstart">&#8220;</span><p><?PHP echo '' .nl2br($row["testimonial"]) . '';?></p><span class="bqend">&#8221;</span></blockquote> 
    <p class="highlight"><?PHP echo '' . $row["name"] . '';?></p>
    <br clear='all' />

    <?php
}

echo $paginate;

mysql_close($DB);
?>

我已经删除了大部分分页代码,但这只是为了向您展示如何更简单地实现它。

【讨论】:

  • 非常感谢 gmadd。请教我如何改进它。
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