【问题标题】:iOS link two firebase accountiOS链接两个firebase帐户
【发布时间】:2018-04-10 09:28:45
【问题描述】:

我正在尝试链接两个 firebase 帐户,通常用户会使用社交媒体或电子邮件或匿名帐户登录,然后用户会使用电话登录。我需要链接这两个帐户。

父视图

将调用父视图中的函数以使用电话号码进行注册

class welcomeView: UIViewController, FUIAuthDelegate {

 //stores current user
 var previosUser = FIRUser()


 override func viewDidLoad() {
    super.viewDidLoad()
  if let user = Auth.auth().currentUser {
        previosUser = user 
    }else{
        Auth.auth().signInAnonymously() { (user, error) in

            if error != nil {
                //handle error
            }
            previosUser = user!
        }
    }

 }






 func signUpWithPhone(){ 
    let vc = signUpWithPhoneView()
    vc.authUI?.delegate = self
    vc.auth?.languageCode = "ar"
    self.present(vc, animated: true) 

  }


}

在子视图(signUpWithPhoneView)中,我展示了 FUIPhoneAuth

phoneProvider.signIn(withPresenting: self)

子视图

import UIKit
import FirebaseAuthUI
import FirebasePhoneAuthUI

class signUpWithPhoneView: UIViewController {

 fileprivate(set) var authUI = FUIAuth.defaultAuthUI()
 var didload = false

 override func viewDidLoad() {
    super.viewDidLoad()
 }


 override func viewWillAppear(_ animated: Bool) {
    if !didload { // stops from looping 
        didload = !didload

        guard let authUI = self.authUI else {return}
        let phoneProvider = FUIPhoneAuth.init(authUI: authUI)
        self.authUI?.providers = [phoneProvider] 
     >> phoneProvider.signIn(withPresenting: self)

    }
 }


}

当用户登录时,子视图将自动关闭,我有 didSignInWith 函数,该函数将在父视图中调用。我需要关联之前的用户账号和用户手机账号

父视图

    func authUI(_ authUI: FUIAuth, didSignInWith user: FirebaseAuth.User?, error: Error?) {

    if let user = user{

        // link the the two accounts

    }else{

    }

}

我尝试使用链接

        let provider = PhoneAuthProvider.provider(auth: authUI.auth!)
        let credential = PhoneAuthProvider.credential(provider)


        previosUser.link(with: credential, completion: { (user, error) in
            if error != nil {
                print("this is linking two acounts error : " , error)
            }
        })

但是凭证有错误

...previosUser.link(with: *credential*, completion: ...

Cannot convert value of type '(String, String) -> PhoneAuthCredential' to expected 
argument type 'AuthCredential'

任何帮助将不胜感激 谢谢

【问题讨论】:

    标签: ios swift firebase hyperlink account


    【解决方案1】:

    您正在使用authUI.auth 获取提供程序,然后没有使用它来获取凭据,并且您当前正在使用实例方法credential 的静态引用。

    实例方法本身接受两个字符串并返回一个AuthCredential,这就是您看到(String, String) -> AuthCredential 的原因。您必须使用您必须从用户那里收集的验证 ID 和代码来创建凭据。

    guard let auth = authUI.auth else { return }
    
    let provider = PhoneAuthProvider.provider(auth: auth)
    let credential = provider.credential(
       withVerificationID: "XXXXXXXXXXXX", 
       verificationCode: "XXXXXX"
    )
    
    // ...
    

    【讨论】:

    • 感谢这为我清除了它,但是,如果我使用 firbsaeUI,如何收集 withVerificationID、verificationCode ?使用 FUIPhoneAuth.init(authUI: authUI).signIn(withPresenting: self)
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