在 Openshift 上部署的 Tomcat 应用程序返回 404

Question

我已经在以下网址下部署了我的应用程序：https://migawka-hatak.rhcloud.com/， 但我经常得到 404 状态。 相同的应用程序适用于我本地的 Tomcat 或 Jetty。访问 localhost:8080/ROOT/ 时会返回默认的 Openshift 索引页面。

从 openshift 的日志中我可以看到它已经启动：

INFO: Starting Servlet Engine: Apache Tomcat/7.0.54
Nov 05, 2014 4:14:32 AM org.apache.catalina.startup.HostConfig deployWAR
INFO: Deploying web application archive /var/lib/openshift/5458e7d3500446ea91000597/app-root/runtime/dependencies/jbosse
ws/webapps/ROOT.war
SLF4J: The requested version 1.5.8 by your slf4j binding is not compatible with [1.6]
SLF4J: See http://www.slf4j.org/codes.html#version_mismatch for further details.
47 [localhost-startStop-1] INFO org.quartz.impl.StdSchedulerFactory - Using default implementation for ThreadExecutor
53 [localhost-startStop-1] INFO org.quartz.simpl.SimpleThreadPool - Job execution threads will use class loader of threa
d: localhost-startStop-1
148 [localhost-startStop-1] INFO org.quartz.core.SchedulerSignalerImpl - Initialized Scheduler Signaller of type: class
org.quartz.core.SchedulerSignalerImpl
150 [localhost-startStop-1] INFO org.quartz.core.QuartzScheduler - Quartz Scheduler v.2.2.1 created.
158 [localhost-startStop-1] INFO org.quartz.simpl.RAMJobStore - RAMJobStore initialized.
160 [localhost-startStop-1] INFO org.quartz.core.QuartzScheduler - Scheduler meta-data: Quartz Scheduler (v2.2.1) 'Defau
ltQuartzScheduler' with instanceId 'NON_CLUSTERED'
  Scheduler class: 'org.quartz.core.QuartzScheduler' - running locally.
  NOT STARTED.
  Currently in standby mode.
  Number of jobs executed: 0
  Using thread pool 'org.quartz.simpl.SimpleThreadPool' - with 10 threads.
  Using job-store 'org.quartz.simpl.RAMJobStore' - which does not support persistence. and is not clustered.
161 [localhost-startStop-1] INFO org.quartz.impl.StdSchedulerFactory - Quartz scheduler 'DefaultQuartzScheduler' initial
ized from default resource file in Quartz package: 'quartz.properties'
161 [localhost-startStop-1] INFO org.quartz.impl.StdSchedulerFactory - Quartz scheduler version: 2.2.1
Nov 05, 2014 4:14:40 AM org.apache.catalina.startup.HostConfig deployWAR
INFO: Deployment of web application archive /var/lib/openshift/5458e7d3500446ea91000597/app-root/runtime/dependencies/jb
ossews/webapps/ROOT.war has finished in 7,523 ms
Nov 05, 2014 4:14:40 AM org.apache.coyote.AbstractProtocol start
INFO: Starting ProtocolHandler ["http-bio-127.9.148.1-8080"]
Nov 05, 2014 4:14:40 AM org.apache.catalina.startup.Catalina start
INFO: Server startup in 7825 ms

我在上下文监听器中使用了quartz，我的应用也是基于RestEasy 框架的。 知道发生了什么吗？

Answer 1

我已经解决了问题，通过从头开始重新创建应用程序，唯一的区别是我使用了来自 tmplate 的 web.xml 而不是我的。

web.xml 现在有什么不同：

 <web-app version="3.0" 
    xmlns="java.sun.com/xml/ns/javaee" 
    xmlns:xsi="w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="java.sun.com/xml/ns/javaee java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
    metadata-complete="false">

</web-app>