如何使用 gmail api 获取我的 gmail 帐户的每封邮件的正文？

Question

我正在尝试使用 google oauth 和 gmail api 服务解析我的 gmail 帐户中的每一个邮件正文。按照现在，我只能获取消息 id 和线程 id，当我打开它们时，它根本没有意义。 所以我使用的以下代码如下：

from __future__ import print_function
import pickle
import os.path
from googleapiclient.discovery import build
from google_auth_oauthlib.flow import InstalledAppFlow
from google.auth.transport.requests import Request

# If modifying these scopes, delete the file token.pickle.
SCOPES = ['https://www.googleapis.com/auth/gmail.readonly']

def main():
    """Shows basic usage of the Gmail API.
    Lists the user's Gmail labels.
    """
    creds = None
    # The file token.pickle stores the user's access and refresh tokens, and is
    # created automatically when the authorization flow completes for the first
    # time.
    if os.path.exists('token.pickle'):
        with open('token.pickle', 'rb') as token:
            creds = pickle.load(token)
    # If there are no (valid) credentials available, let the user log in.
    if not creds or not creds.valid:
        if creds and creds.expired and creds.refresh_token:
            creds.refresh(Request())
        else:
            flow = InstalledAppFlow.from_client_secrets_file(
                'credentials.json', SCOPES)
            creds = flow.run_local_server()
        # Save the credentials for the next run
        with open('token.pickle', 'wb') as token:
            pickle.dump(creds, token)

    service = build('gmail', 'v1', credentials=creds)

    # Call the Gmail API
    results = service.users().labels().list(userId='me').execute()
    print(service.users().messages().list(userId='me').execute())
    print(service.users().messages().get(userId='me', id='16931216e3a05048').execute())
    labels = results.get('labels', [])

    if not labels:
        print('No labels found.')
    else:
        print('Labels:')
        for label in labels:
            print(label['name'])

if __name__ == '__main__':
    main()

我得到的输出是这样的，其中一个消息 id 使用这一行 print(service.users().messages().get(userId='me', id='16931216e3a05048').execute())

输出是这样的：

Answer 1

你忘了添加格式

messages.get

message = service.users().messages().get(userId=user_id, id=msg_id,
                                         format='raw').execute()

print 'Message snippet: %s' % message['snippet']

msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))

mime_msg = email.message_from_string(msg_str)