【发布时间】：2015-03-16 02:27:28
【问题描述】：
我需要在 figureCanvas 中有 2 个可拖动的点。但我有一个补充约束：这两个点必须用一条线连接起来。 当然，当我拖动一个点时（否则就不好笑了），这条线必须是动态绘制的，并且仍然链接到这两个点。
我设法用这个主题创建了 2 个可拖动点： Matplotlib drag overlapping points interactively
我修改了一些代码以通过 FigureCanvas 的子类使用它（稍后将图形包含在 PyQt 应用程序中）：
import matplotlib.pyplot as plt
import matplotlib.patches as patches
class DraggablePoint:
# https://stackoverflow.com/questions/21654008/matplotlib-drag-overlapping-points-interactively
lock = None # only one can be animated at a time
def __init__(self, parent, x=0.1, y=0.1):
self.parent = parent
self.point = patches.Ellipse((x, y), 0.01, 0.03, fc='r', alpha=0.5)
self.x = x
self.y = y
parent.fig.axes[0].add_patch(self.point)
self.press = None
self.background = None
self.connect()
def connect(self):
'connect to all the events we need'
self.cidpress = self.point.figure.canvas.mpl_connect('button_press_event', self.on_press)
self.cidrelease = self.point.figure.canvas.mpl_connect('button_release_event', self.on_release)
self.cidmotion = self.point.figure.canvas.mpl_connect('motion_notify_event', self.on_motion)
def on_press(self, event):
if event.inaxes != self.point.axes: return
if DraggablePoint.lock is not None: return
contains, attrd = self.point.contains(event)
if not contains: return
self.press = (self.point.center), event.xdata, event.ydata
DraggablePoint.lock = self
# draw everything but the selected rectangle and store the pixel buffer
canvas = self.point.figure.canvas
axes = self.point.axes
self.point.set_animated(True)
canvas.draw()
self.background = canvas.copy_from_bbox(self.point.axes.bbox)
# now redraw just the rectangle
axes.draw_artist(self.point)
# and blit just the redrawn area
canvas.blit(axes.bbox)
def on_motion(self, event):
if DraggablePoint.lock is not self:
return
if event.inaxes != self.point.axes: return
self.point.center, xpress, ypress = self.press
dx = event.xdata - xpress
dy = event.ydata - ypress
self.point.center = (self.point.center[0]+dx, self.point.center[1]+dy)
canvas = self.point.figure.canvas
axes = self.point.axes
# restore the background region
canvas.restore_region(self.background)
# redraw just the current rectangle
axes.draw_artist(self.point)
# blit just the redrawn area
canvas.blit(axes.bbox)
def on_release(self, event):
'on release we reset the press data'
if DraggablePoint.lock is not self:
return
self.press = None
DraggablePoint.lock = None
# turn off the rect animation property and reset the background
self.point.set_animated(False)
self.background = None
# redraw the full figure
self.point.figure.canvas.draw()
self.x = self.point.center[0]
self.y = self.point.center[1]
def disconnect(self):
'disconnect all the stored connection ids'
self.point.figure.canvas.mpl_disconnect(self.cidpress)
self.point.figure.canvas.mpl_disconnect(self.cidrelease)
self.point.figure.canvas.mpl_disconnect(self.cidmotion)
未来图上只会有 2 个点，我可以通过 self.parent 类从 DraggablePoint 类访问另一个点。
我想我需要在函数 on_motion 中在两点之间画一条线。但我试过了，一无所获。 你知道如何实现这一目标吗？
【问题讨论】：
标签： python matplotlib pyqt