Tkinter：等待多个按钮中的任何一个被按下，然后删除所有按钮

Question

我有一个带有两个按钮的界面。它们具有互斥的动作，并且在满足后台 for 循环中的某个条件时生成。用户应该单击其中一个按钮，然后按钮应该消失。当在后台运行 for 循环中再次满足条件时，它们可能会重新出现。你可以想到做“选择其中一个……”类型的事情的按钮。后台的for循环需要等待用户输入。因此，我在按钮上使用了wait_variable 方法。

为了建模，我写了这个 MWE：

import tkinter as tk

root = tk.Tk()

a, b = 0, 0

var = tk.IntVar()

def Aaction():
    global a
    a += 1
    var.set(var.get()+1)
    b1.destroy()
    b2.destroy()

def Baction():
    global b
    b += 1
    var.set(var.get()+1)
    b1.destroy()
    b2.destroy()

# this happens before A and B are displayed
print('some code executing')

b1 = tk.Button(root, text='A', command=Aaction)
b1.pack()

b2 = tk.Button(root, text='B', command=Baction)
b2.pack()

b1.wait_variable(var)
print('b1 finsihed waiting')
b2.wait_variable(var) # what happens to this? `b2` is deleted when `b` is clicked. so...?
print('b2 finsihed waiting') # this is never reached

# this should happen after either A or B was clicked
print('some more code executing')

root.mainloop()

这段代码不是我想要的，但它是我试图在我的代码中解决这个问题的抽象。我的问题是：你如何正确解决这个问题？

Answer 1

这样的东西可以吗？

import tkinter as tk

root = tk.Tk()

def Aaction():
    b1.destroy()
    b2.destroy()
    do_later()

def Baction():
    b1.destroy()
    b2.destroy()
    do_later()

# this happens before A and B are displayed
print('some code executing')

b1 = tk.Button(root, text='A', command=Aaction)
b1.pack()

b2 = tk.Button(root, text='B', command=Baction)
b2.pack()

# this should happen after either A or B was clicked
def do_later():
    print('some more code executing')

root.mainloop()