【发布时间】:2017-06-15 00:36:43
【问题描述】:
我有一个从 json URI (http://api.androidhive.info/feed/feed.json) 获取内容并在列表视图中显示内容的活动。
内容包括图片、帖子的URI、描述等。每个内容项都有自己的URI。
我不想使用网络浏览器打开点击的 URI,而是希望在具有 web 视图的 另一个 活动中打开它。
很抱歉再次提出这个问题,我遇到了问题。我从http:// www.androidhive.info/2014/06/android-facebook-like-custom-listview-feed-using-volley 获得了一个运行良好的源代码,并且我在尝试传递点击链接以在应用程序 web 视图中打开时遇到问题。
这是 JSON 数据
{
"feed": [
{
"id": 2,
"name": "TIME",
"image": "http://api.androidhive.info/feed/img/time_best.jpg",
"status": "30 years of Cirque du Soleil's best photos",
"profilePic": "http://api.androidhive.info/feed/img/time.png",
"timeStamp": "1403375851930",
"url": "http://ti.me/1qW8MLB"
},
{
"id": 11,
"name": "A. R. rahman",
"image": "http://api.androidhive.info/feed/img/ar_bw.jpg",
"status": "",
"profilePic": "http://api.androidhive.info/feed/img/ar.jpg",
"timeStamp": "1403375851930",
"url": ""
}
]
}
这是 MainActivity.java
package info.androidhive.listviewfeed;
public class MainActivity extends Activity {
private static final String TAG = MainActivity.class.getSimpleName();
private ListView listView;
private FeedListAdapter listAdapter;
private List<FeedItem> feedItems;
private String URL_FEED = "http://api.androidhive.info/feed/feed.json";
@SuppressLint("NewApi")
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
listView = (ListView) findViewById(R.id.list);
feedItems = new ArrayList<FeedItem>();
listAdapter = new FeedListAdapter(this, feedItems);
listView.setAdapter(listAdapter);
// These two lines not needed,
// just to get the look of facebook (changing background color & hiding the icon)
getActionBar().setBackgroundDrawable(new ColorDrawable(Color.parseColor("#3b5998")));
getActionBar().setIcon(
new ColorDrawable(getResources().getColor(android.R.color.transparent)));
// We first check for cached request
Cache cache = AppController.getInstance().getRequestQueue().getCache();
Entry entry = cache.get(URL_FEED);
if (entry != null) {
// fetch the data from cache
try {
String data = new String(entry.data, "UTF-8");
try {
parseJsonFeed(new JSONObject(data));
} catch (JSONException e) {
e.printStackTrace();
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
} else {
// making fresh volley request and getting json
JsonObjectRequest jsonReq = new JsonObjectRequest(Method.GET,
URL_FEED, null, new Response.Listener<JSONObject>() {
@Override
public void onResponse(JSONObject response) {
VolleyLog.d(TAG, "Response: " + response.toString());
if (response != null) {
parseJsonFeed(response);
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
VolleyLog.d(TAG, "Error: " + error.getMessage());
}
});
// Adding request to volley request queue
AppController.getInstance().addToRequestQueue(jsonReq);
}
}
/**
* Parsing json reponse and passing the data to feed view list adapter
* */
private void parseJsonFeed(JSONObject response) {
try {
JSONArray feedArray = response.getJSONArray("feed");
for (int i = 0; i < feedArray.length(); i++) {
JSONObject feedObj = (JSONObject) feedArray.get(i);
FeedItem item = new FeedItem();
item.setId(feedObj.getInt("id"));
item.setName(feedObj.getString("name"));
// Image might be null sometimes
String image = feedObj.isNull("image") ? null : feedObj
.getString("image");
item.setImge(image);
item.setStatus(feedObj.getString("status"));
item.setProfilePic(feedObj.getString("profilePic"));
item.setTimeStamp(feedObj.getString("timeStamp"));
// url might be null sometimes
String feedUrl = feedObj.isNull("url") ? null : feedObj
.getString("url");
item.setUrl(feedUrl);
feedItems.add(item);
}
// notify data changes to list adapater
listAdapter.notifyDataSetChanged();
} catch (JSONException e) {
e.printStackTrace();
}
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
}
这是我从http:// api.androidhive.info/feed/feed.json 获得的链接被传递并在点击时在 webview 中打开时创建的 webview.java
public class webview extends Activity{
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.webview);
String getStringFromEdittext = "https:// www.google.co.in"+ getIntent().getExtras().getString("text");
WebView wb = (WebView)findViewById(R.id.webView1);
wb.setWebViewClient(new WebViewClient());
System.out.println("URL"+getStringFromEdittext);
wb.loadUrl(getStringFromEdittext );
wb.getSettings().setJavaScriptEnabled(true);
Button button = (Button)findViewById(R.id.button1);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Intent intent = new Intent(getApplicationContext(), MainActivity.class);
startActivity(intent);
}
});
}
}
【问题讨论】:
-
请将您的代码全部格式化为代码。
-
你想达到什么目的?在另一个活动或同一个网页视图中打开?
-
MainActivity 不是 webview,它从 json 服务器获取数据并显示它我希望在另一个包含 webview 的 Activity 中打开 url
-
您还需要答案吗?
-
我真的需要像奥巴马喷气机一样紧急和快速的答案
标签: java android json webview move