【发布时间】:2013-06-29 13:54:48
【问题描述】:
我无法在这里解析我的 XML。它仅返回“项目”。
我的AndroidActivity 很大,无法显示。所以我只展示了负责解析的部分。
我的 XML 看起来像这样:
<MyResource>
<Item>First</Item>
<Item>Second</Item>
</MyResource>
我的ActivityClass方法:
public class ShowItems extends Activity{
ListView lv;
ListAdapter adapter;
static final String KEY_RESOURCE = "MyResource"; // parent node
static final String KEY_ITEM = "Item";
ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
String[] from={KEY_ITEM };
int[] to={R.id.mylist_item};
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.showitems);
lv=(ListView) findViewById(R.id.lv_items);
parseXML();
adapter = new SimpleAdapter(this, mylist,R.layout.list_item,from , to);
lv.setAdapter(adapter);
}
private void parseXML() {
// TODO Auto-generated method stub
XMLParser parser = new XMLParser();
final String URL="http://10.0.2.2:8080/MySite/xml";
String xml = parser.getXmlFromUrl(URL);
Document doc = parser.getDomElement(xml);
NodeList nl = doc.getElementsByTagName(KEY_RESOURCE);
for (int i = 0; i < nl.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM));
mylist.add(map); }
}
我的 XML 解析器类:
import java.io.IOException;
import java.io.StringReader;
import java.io.UnsupportedEncodingException;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import org.apache.http.util.EntityUtils;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;
import android.util.Log;
public class XMLParser {
public String getXmlFromUrl(String url) {
String xml = null;
try {
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return xml;
}
public Document getDomElement(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
return null;
}
// return DOM
return doc;
}
public String getValue(Element item, String str) {
NodeList n = item.getElementsByTagName(str);
return this.getElementValue(n.item(0));
}
public final String getElementValue( Node elem ) {
Node child;
if( elem != null){
if (elem.hasChildNodes()){
for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){
if( child.getNodeType() == Node.TEXT_NODE ){
return child.getNodeValue();
}
}
}
}
return "";
}
}
我无法在这里解析我的 XML。这里有什么问题?
它仅返回“项目”。
我需要在我的ActivityClass 中做什么,尤其是在这部分代码中?
String xml = parser.getXmlFromUrl(URL);
Document doc = parser.getDomElement(xml);
NodeList nl = doc.getElementsByTagName(KEY_RESOURCE);
for (int i = 0; i < nl.getLength(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
Element e = (Element) nl.item(i);
map.put(KEY_ITEM, parser.getValue(e, KEY_ITEM));
mylist.add(map); }
【问题讨论】:
-
我不知道你想要什么,你能说清楚点吗?
-
您会看到他的 XML。他有两个
<Item>标签需要通过DOM 进行解析。而当他通过上述方法解析它时,只解析第一个<Item>标签,其他(或其余的)被忽略。 -
@AltairRules: 1) 您是否将“第一”(或)“第二”作为输入? 2) 你能打印并查看 NodeList nl = doc.getElementsByTagName(KEY_RESOURCE); 的大小吗?
-
我的意思是“第二”作为输出,而不是输入
-
当我这样做时,我将输出为“项目”:
System.out.println(mylist);
标签: android dom xml-parsing android-xml