【发布时间】:2014-03-24 11:41:00
【问题描述】:
如何防止 Boost Spirit Symbol 解析器在以有效关键字(符号)开头时接受关键字(符号)。我希望该构造无法整体解析“ONEMORE”并且无法成功解析“ONE”,因为这是一个有效的关键字,然后在“MORE”上失败。
下面是代码的实际输出:
Keyword as a number: 1
Keyword as a number: 2
Keyword as a number: 1
Invalid keyword: MORETHREE
这就是我喜欢的样子:
Keyword as a number: 1
Keyword as a number: 2
Invalid keyword: ONEMORE
Keyword as a number: 3
代码只是说明问题的一个示例。
#include <boost/config/warning_disable.hpp>
#include <boost/spirit/include/qi.hpp>
#include <iostream>
#include <string>
using namespace std;
namespace qi = boost::spirit::qi;
namespace ascii = boost::spirit::ascii;
void printNumber( unsigned u )
{
cout << "Keyword as a number: " << u << endl;
}
void printInvalidKeyword( const string &s )
{
cout << "Invalid keyword: " << s << endl;
}
template <typename Iterator>
struct keyword_parser : qi::grammar<Iterator, ascii::space_type>
{
struct mySymbols_ : qi::symbols<char, unsigned>
{
mySymbols_()
{
add
("ONE" , 1)
("TWO" , 2)
("THREE" , 2)
;
}
} mySymbols;
keyword_parser() : keyword_parser::base_type(start)
{
using qi::_1;
using qi::raw;
using ascii::char_;
start %= *(
mySymbols[&printNumber]
|
invalid[&printInvalidKeyword]
);
invalid = +char_;
}
qi::rule<Iterator, ascii::space_type> start;
qi::rule<Iterator, std::string(), ascii::space_type> invalid;
};
int main()
{
using boost::spirit::ascii::space;
typedef std::string::const_iterator iterator_type;
typedef keyword_parser<iterator_type> keyword_parser;
std::string s = "ONE TWO ONEMORE THREE";
iterator_type b = s.begin();
iterator_type e = s.end();
phrase_parse(b, e, keyword_parser(), space);
return 0;
}
【问题讨论】:
标签: c++ boost symbols boost-spirit