在开始日期和结束日期之间获取每月的第三个星期六

Question

我想获取两个日期之间每月第三个星期六的日期。我已经完成了，但这不是我想要的。

NSInteger count = 0;
NSInteger saturday = 7;

// Set the incremental interval for each interaction.
NSDateComponents *oneDay = [[NSDateComponents alloc] init];
[oneDay setDay:1];

// Using a Gregorian calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSDate *currentDate = [[UtilityClass sharedObject] stringToDate:@"2016-06-17" withFormate:@"yyyy-MM-dd"];
        NSDate *toDate = [[UtilityClass sharedObject] stringToDate:@"2016-08-17" withFormate:@"yyyy-MM-dd"];


// Iterate from fromDate until toDate
while ([currentDate compare:toDate] == NSOrderedAscending) {

NSDateComponents *dateComponents = [calendar components:NSWeekdayCalendarUnit fromDate:currentDate];
[dateComponents setWeekdayOrdinal:3];

if (dateComponents.weekday == saturday) {
    count++;
    NSLog(@"Date = %@",currentDate);
}

// "Increment" currentDate by one day.
currentDate = [calendar dateByAddingComponents:oneDay
                                                    toDate:currentDate
                                                   options:0];
}

在我的代码中，我已成功获得星期六，但所有星期六都在 startdate 和 enddate 之间。 我也试过这个：

[dateComponents setWeekdayOrdinal:3]; 但不工作。

这是我的日志

2016-06-17 11:29:18.319 Floacstation[1715:84848] Current Date :2016-06-16 18:30:00 +0000
2016-06-17 11:29:18.319 Floacstation[1715:84848] To Date : 2016-08-16 18:30:00 +0000

2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-06-19 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-06-26 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-07-03 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-07-10 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-07-17 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-07-24 18:30:00 +0000
2016-06-17 11:29:18.320 Floacstation[1715:84848] Saturday Date = 2016-07-31 18:30:00 +0000
2016-06-17 11:29:18.321 Floacstation[1715:84848] Saturday Date = 2016-08-07 18:30:00 +0000
2016-06-17 11:29:18.321 Floacstation[1715:84848] Saturday Date = 2016-08-14 18:30:00 +0000

Answer 1

原因：

请注意，您输入了日期17th，但它返回给您16th.. 因为它正在考虑UTC 格式，只要您是printing NSDate in NSLog 或converting it explicitly to NSString。

只要你想要字符串中的日期，就使用我在本代码中使用的NSDateFormatter..

您所面临的问题正是因为如此。 所以，无论你在哪里使用日期，只需将replace the method of converting date 放入字符串并再次检查输出..

试试这个……它一定会给你正确的答案……

NSInteger count = 0;
NSInteger saturday = 7;

// Set the incremental interval for each interaction.
NSDateComponents *oneDay = [[NSDateComponents alloc] init];
[oneDay setDay:1];

// Using a Gregorian calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSDate *currentDate = [[UtilityClass sharedObject] stringToDate:@"2016-06-17" withFormate:@"yyyy-MM-dd"];
        NSDate *toDate = [[UtilityClass sharedObject] stringToDate:@"2016-08-17" withFormate:@"yyyy-MM-dd"];


// Iterate from fromDate until toDate
while ([currentDate compare:toDate] == NSOrderedAscending) {

NSDateComponents *dateComponents = [calendar components:NSWeekdayCalendarUnit fromDate:currentDate];
[dateComponents setWeekdayOrdinal:3];

if (dateComponents.weekday == saturday) {
    count++;

    if (count==3) {
            NSDateFormatter *formatter=[[NSDateFormatter alloc]init];
            formatter.dateFormat=@"dd MM YYYY";

            NSLog(@"Date = %@",[formatter stringFromDate:currentDate]);
        }
  }

}   

// 不需要增加这个日期..

// "Increment" currentDate by one day.
// currentDate = [calendar dateByAddingComponents:oneDay
//                                                    toDate:currentDate
//                                                   options:0];

希望这会有所帮助... :)

Answer 2

NSCalendar 拥有强大的技能，无需重复循环

NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian];
NSDate *currentDate = [[UtilityClass sharedObject] stringToDate:@"2016-06-17" withFormate:@"yyyy-MM-dd"];
NSDate *toDate = [[UtilityClass sharedObject] stringToDate:@"2016-08-17" withFormate:@"yyyy-MM-dd"];

NSDateComponents *components = [[NSDateComponents alloc] init];
components.weekday = 7;
components.weekdayOrdinal = 3;
components.month = [calendar component:NSCalendarUnitMonth fromDate:currentDate];

NSDate *nextThirdSaturday = [calendar nextDateAfterDate:currentDate matchingComponents: components options: NSCalendarMatchNextTime];
if (nextThirdSaturday && [nextThirdSaturday compare:toDate] == NSOrderedAscending) {
   NSLog(@"%@", nextThirdSaturday);
} else {
   NSLog(@"Not Found");
}

编辑：

如果你想从开始日期计算第三个星期六并且在开始和结束日期的范围内使用这个

NSDateComponents *components = [[NSDateComponents alloc] init];
components.weekday = 7;

__block NSInteger count = 1;
__block NSDate *found;
[calendar enumerateDatesStartingAfterDate:currentDate matchingComponents:components options:NSCalendarMatchNextTime usingBlock:^(NSDate *date, BOOL exactMatch, BOOL *stop) {
   if (count == 3) { found = date; }
   if  (found || [date compare:toDate] == NSOrderedDescending) *stop = YES;
   count++;
}];
NSLog(@"%@", found);

Answer 3

据我了解，你要的日期是2016-07-02？ 试试这个：

NSDate *currentDate = [NSDate dateWithString:@"2016-06-16" formatString:@"yyyy-MM-dd"];

NSDate *toDate = [NSDate dateWithString:@"2016-08-17" formatString:@"yyyy-MM-dd"];

NSLog(@"Oh, %@ is the 3rd Saturday", [[currentDate dateByAddingWeeks:2] dateByAddingDays:(saturday - currentDate.weekday + 1)]);

我使用名为 DateTools 的第三个库。

Answer 4

NSInteger count = 0;
NSInteger saturday = 7;

// Set the incremental interval for each interaction.
NSDateComponents *oneDay = [[NSDateComponents alloc] init];
[oneDay setDay:1];

// Using a Gregorian calendar.
NSCalendar *calendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];

NSDate *currentDate = [[UtilityClass sharedObject] stringToDate:@"2016-06-17" withFormate:@"yyyy-MM-dd"];
        NSDate *toDate = [[UtilityClass sharedObject] stringToDate:@"2016-08-17" withFormate:@"yyyy-MM-dd"];


// Iterate from fromDate until toDate
while ([currentDate compare:toDate] == NSOrderedAscending) {

NSDateComponents *dateComponents = [calendar components:NSWeekdayCalendarUnit fromDate:currentDate];
[dateComponents setWeekdayOrdinal:3];

if (dateComponents.weekday == saturday) {
    count++;
    NSLog(@"3rd Satureday Date = %@",currentDate);
    if(count == 3)
        break;
}

// "Increment" currentDate by one day.
currentDate = [calendar dateByAddingComponents:oneDay
                                                    toDate:currentDate
                                                   options:0];
}

这是我的日志

2016-06-17 11:07:53.335 Floacstation[1568:75953] Date = 2016-06-17 18:30:00 +0000
2016-06-17 11:07:53.335 Floacstation[1568:75953] Date = 2016-06-24 18:30:00 +0000
2016-06-17 11:07:53.335 Floacstation[1568:75953] Date = 2016-07-01 18:30:00 +0000
2016-06-17 11:07:53.335 Floacstation[1568:75953] Date = 2016-07-08 18:30:00 +0000
2016-06-17 11:07:53.335 Floacstation[1568:75953] Date = 2016-07-15 18:30:00 +0000
2016-06-17 11:07:53.336 Floacstation[1568:75953] Date = 2016-07-22 18:30:00 +0000
2016-06-17 11:07:53.336 Floacstation[1568:75953] Date = 2016-07-29 18:30:00 +0000
2016-06-17 11:07:53.336 Floacstation[1568:75953] Date = 2016-08-05 18:30:00 +0000
2016-06-17 11:07:53.336 Floacstation[1568:75953] Date = 2016-08-12 18:30:00 +0000