在大型 CSV 文件中搜索和修改列答案

【问题标题】：Search and Modify Column in Large CSV FIle在大型 CSV 文件中搜索和修改列
【发布时间】：2014-04-16 05:06:20
【问题描述】：

我有一些大的 CSV 文件，格式如下（用逗号分隔）

2014.03.11 14:59:59.146,67.1547,67.15507,0.02,0.02
2014.03.11 14:59:59.206,67.15405,67.15437,0.02,0.02
2014.03.11 14:59:59.506,67.15552,67.15589,0.02,0.02
2014.03.11 14:59:59.707,67.15581,67.15616,0.02,0.02

现在我想完成这个任务。

第 2 列和第 3 列的多个 100

结果应该是这样的

2014.03.11 14:59:59.146,6715.47,6715.507,0.02,0.02
2014.03.11 14:59:59.206,6715.405,6715.437,0.02,0.02
2014.03.11 14:59:59.506,6715.552,6715.589,0.02,0.02
2014.03.11 14:59:59.707,6715.581,6715.616,0.02,0.02

非常感谢您的帮助。谢谢

【问题讨论】：

标签： windows perl unix sed awk

【解决方案1】：

这个awk 应该这样做：

awk '{$2*=100;$3*=100}1' FS=, OFS=, file
2014.03.11 14:59:59.146,6715.47,6715.51,0.02,0.02
2014.03.11 14:59:59.206,6715.4,6715.44,0.02,0.02
2014.03.11 14:59:59.506,6715.55,6715.59,0.02,0.02
2014.03.11 14:59:59.707,6715.58,6715.62,0.02,0.02

您可以使用$2=$2*100 或仅使用$2*=100 将一列乘以100

【讨论】：

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【解决方案2】：

perl -F/,/ -lape "$F[$_] *= 100 for (1,2); $_ = join',', @F;" < input.csv > output.csv

【讨论】：