替换 terraform 文件中的代码块答案

【问题标题】：replace code block in terraform file替换 terraform 文件中的代码块
【发布时间】：2017-10-05 22:49:37
【问题描述】：

我正在我的 Jenkins 服务器上运行构建，我希望使用当前构建中的提交号动态填充 git_commit 字段。该文件中有多个函数，我想使用 sed 匹配模块的 core-lambda-function1 名称，并使用当前构建中的提交号更新 git_commit 字段。任何帮助表示赞赏。谢谢。

module "core-lambda-function1" {
  source  = "./lambda"
  name    = "core-lambda-function"
  runtime = "nodejs6.10"
  role    = "${aws_iam_role.iam_role_for_lambda.arn}"
  filename = "../Archive.zip"
  source_code_hash  = "${base64sha256(file("../Archive.zip"))}"
  source_dir = "../"
  git_commit = ""
}

module "core-lambda-function2" {
  source  = "./lambda"
  name    = "core-lambda-function"
  runtime = "nodejs6.10"
  role    = "${aws_iam_role.iam_role_for_lambda.arn}"
  filename = "../Archive.zip"
  source_code_hash  = "${base64sha256(file("../Archive.zip"))}"
  source_dir = "../"
  git_commit = ""
}

这是我目前拥有的。

#!/bin/bash
set -e

while read p; do
  NAME=$p
  GIT_COMMIT=`git rev-parse HEAD`
  echo $NAME | grep `xargs` main.tf -A 7 | sed -ri '7s/git_commit = ""/git_commit\ = \"'$GIT_COMMIT'"/g'
done < build_name

【问题讨论】：

标签： bash jenkins sed aws-lambda terraform

【解决方案1】：

为什么不Input Variables in Terraform？

variable "git_commit" {}

module "core-lambda-function1" {
  source  = "./lambda"
  name    = "core-lambda-function"
  runtime = "nodejs6.10"
  role    = "${aws_iam_role.iam_role_for_lambda.arn}"
  filename = "../Archive.zip"
  source_code_hash  = "${base64sha256(file("../Archive.zip"))}"
  source_dir = "../"
  git_commit = "${var.git_commit}"      #### Use variable here.
}

因此，在您的包装脚本中，您可以更新为：

#!/bin/bash
set -e

GIT_COMMIT=$(git rev-parse HEAD)

terraform plan -var 'git_commit=${GIT_COMMIT}' ...

【讨论】：

也像这样：terraform plan -var "git_commit=git rev-parse HEAD"