表格页脚中的 UIButton 无响应答案

【问题标题】：UIButton In Table Footer Unresponsive表格页脚中的 UIButton 无响应
【发布时间】：2011-07-03 06:09:02
【问题描述】：

对于自定义表格页脚，我使用以下代码

- (UIView *)tableView:(UITableView *)tableView viewForFooterInSection:(NSInteger)section {
    if(editmode) {
    if(footerView == nil) {
        //allocate the view if it doesn't exist yet
        footerView  = [[UIView alloc] init];

        //we would like to show a gloosy red button, so get the image first
        UIImage *image = [[UIImage imageNamed:@"button_green.png"] stretchableImageWithLeftCapWidth:8 topCapHeight:8];

        //create the button
        UIButton *button = [UIButton buttonWithType:UIButtonTypeRoundedRect];
        [button setBackgroundImage:image forState:UIControlStateNormal];

        //the button should be as big as a table view cell
        [button setFrame:CGRectMake(10, 3, 300, 44)];

        //set title, font size and font color
        [button setTitle:@"Photo" forState:UIControlStateNormal];
        [button.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
        [button setTitleColor:[UIColor whiteColor] forState:UIControlStateNormal];

        //set action of the button
        [button addTarget:self action:@selector(selectExistingPicture) forControlEvents:UIControlEventTouchUpInside];

        //add the button to the view
        [footerView addSubview:button];
        UIButton *button2 = [UIButton buttonWithType:UIButtonTypeRoundedRect];
        image = [[UIImage imageNamed:@"button_grey_dark.png"] stretchableImageWithLeftCapWidth:8 topCapHeight:8];
        [button2 setBackgroundImage:image forState:UIControlStateNormal];

        //the button should be as big as a table view cell
        [button2 setFrame:CGRectMake(10, 50, 300, 44)];

        //set title, font size and font color
        [button2 setTitle:@"Note" forState:UIControlStateNormal];
        [button2.titleLabel setFont:[UIFont boldSystemFontOfSize:20]];
        [button2 setTitleColor:[UIColor whiteColor] forState:UIControlStateNormal];

        //set action of the button
        [button2 addTarget:self action:@selector(mkFolder) forControlEvents:UIControlEventTouchUpInside];

        //add the button to the view
        [footerView addSubview:button2];

        //      [button setupAsRedButton];
    }

    //return the view for the footer
    return footerView;
    } 
    return nil;
}

使用它，第一个按钮可以完美响应，但是，第二个按钮没有注册任何事件。即使函数不存在，也不会产生空函数错误。关于为什么 UITouchUpInside 没有被识别的任何想法？

【问题讨论】：

标签： iphone xcode uitableview uibutton

【解决方案1】：

哇！！！

在这段代码的正下方，我有

// specify the height of your footer section
- (CGFloat)tableView:(UITableView *)tableView
heightForFooterInSection:(NSInteger)section {
    //differ between your sections or if you
    //have only on section return a static value
    return 50;
}

这会将 UIView 设置为忽略 50 像素以下的任何内容。改成 100 就好了。

【讨论】：