【发布时间】:2018-03-21 06:43:18
【问题描述】:
所以我试图使用双向链表在 deque 上构建这个项目。但是当我建造它时。它说构建但提供线程并且没有按要求提供输出。 我已经一次又一次地重新实现了主要问题(复制构造函数)和所有函数,但它仍然每次都给我新的线程。
这是头文件。
#pragma once
#include <stdexcept>
using namespace std;
class Node
{
public:
int data;
Node* next;
Node* previous;
Node();
Node(const int &x);
};
class Deque
{
public:
Deque();
Deque(const Deque &d);
Deque &operator= (const Deque &d);
~Deque();
void insertFront(const int &x);
void insertBack(const int &x);
int removeFront();
int removeBack();
int peekFront();
int peekBack();
bool empty() const;
int size()const;
friend ostream& operator << (ostream &out, const Deque &d);
private:
Node* front;
Node* rear;
};
这将是 .cpp(实现文件)。
//
// Deque_cmpt225.cpp
// Deque_cmpt225
//
// Created by Aryan Arora on 2017-10-09.
// Copyright © 2017 Aryan Arora. All rights reserved.
//
#include "Deque_cmpt225.h"
#include <iostream>
#include <stdexcept>
using namespace std;
Node:: Node()
{
previous = nullptr;
next = nullptr;
data = 0;
}
Node:: Node(const int &x)
{
Node();
data = x;
}
Deque:: Deque() //Empty Deque.
{
front = nullptr;
rear = nullptr;
}
Deque:: ~Deque()
{
if (this->empty())
return;
else{
Node* temp;
while (this->front->next != nullptr){
temp = this->front;
this->front = this->front->next;
delete temp;
}
temp = this->front;
this->front = nullptr;
this->rear = nullptr;
delete temp;
}
}
Deque:: Deque (const Deque &d) //Copy Constructor
{
if (d.empty()) //Deque is empty.
{
return;
}
Node* temp = d.front;
int x;
if (temp->next == nullptr) //Deque of just one node
{
x = temp->data;
Node *n1 = new Node (x);
n1->next = nullptr;
n1->previous = nullptr;
this->front = n1;
this->rear = n1;
}
else //Deque has more than one node
{
while (temp!= nullptr)
{
this->insertBack(temp->data);
temp = temp -> next;
}
}
}
Deque& Deque:: operator=(const Deque &d) //============================check again
{
if (this == &d)
return *this;
else
{
this->~Deque(); //DELETING THE DEQUE
Node* temp = d.front; //COPYING EACH NODE
while (temp != NULL)
{
this->insertBack(temp->data); //INSERTING AT THE BACK
temp = temp->next; //POINTING TEMP TO NEXT NODE
}
}
return *this;
}
void Deque:: insertFront(const int &x)
{
Node* temp = new Node(x);
temp->next = nullptr;
temp->previous = nullptr;
if (empty())
{
this->front = temp;
this->rear = temp;
}
else
{
temp->next = this->front;
temp->previous = nullptr;
this->front->previous = temp;
this->front = temp;
}
}
void Deque:: insertBack(const int &x)
{
Node* temp = new Node(x);
temp->next = nullptr;
temp->previous = nullptr;
if (empty())
{
this->front = temp;
this->rear = temp;
}
else
{
temp->next = nullptr;
temp->previous = this->rear;
this->rear->next = temp;
this->rear = temp;
}
}
int Deque:: removeFront()
{
if (empty()) //=================runtime error
{
throw std::runtime_error("The que is empty.");
}
else{
Node* temp;
temp = this->front;
int x = temp->data;
if ( this->front->next != nullptr )
{
this->front = this->front->next;
this->front->previous = nullptr;
}
else
{
this->front = nullptr;
this->rear = nullptr;
}
delete temp;
return x;
}
}
int Deque:: removeBack()
{
if (empty()) //=================runtime error
{
throw std::runtime_error("The que is empty.");
}
else{
Node* temp = this->rear;
int x = temp->data;
if ( this->rear->previous != nullptr )
{
this->rear = this->rear->previous;
this->rear->next = nullptr;
}
else
{
this->rear = nullptr;
this->front = nullptr;
}
delete temp;
return x;
}
}
int Deque:: peekFront()
{
if (empty()) //=================runtime error
{
throw std::runtime_error("The que is empty.");
}
else
{
return this->front->data;
}
}
int Deque:: peekBack()
{
if (empty()) //=================runtime error
{
throw std::runtime_error("The que is empty.");
}
else
{
return this->rear->data;
}
}
bool Deque:: empty() const
{
if (this->front == nullptr && this->rear == nullptr)
return true;
else
return false;
}
int Deque:: size() const
{
Node* temp = this->front;
int count = 0;
while (temp != nullptr)
{
count++;
temp = temp->next;
}
return count;
}
ostream& operator << (ostream &out, const Deque &d)
{
Node* temp = d.front;
out << "NULL -> ";
while (temp != nullptr)
{
out << temp->data << " <-> ";
temp= temp->next;
}
out << "<- NULL" << endl;
return out;
}
提前致谢。
【问题讨论】:
-
您的复制赋值运算符正在手动调用析构函数..
-
尝试使用复制构造函数。我想知道为什么每当我使用它时,我都会在 insertback 等函数上出现“THREAD 1= EXC_BAD_ACCESS (code=1, address=0x9)”之类的错误。
-
当我什至没有在我的复制构造函数中调用析构函数时,它怎么能手动调用。?
标签: c++ xcode compiler-errors