【发布时间】：2015-03-21 23:14:57
【问题描述】：
我正在尝试在我的 Pycuda 代码中实现一个结构，但我遇到了超出范围的错误。我尝试遵循 this 教程，但无法让它适用于我的案例。
问题很可能是由于指针使用不当造成的，例如本教程显示必须分配指针 memsize 而不是数据 memsize。希望这里有人能给我一些见解...
示例代码：
#!/usr/bin/env python
#-*- coding:utf-8 -*-
import numpy as np
import pycuda.driver as cuda
import pycuda.tools as tools
import pycuda.autoinit
from mako.template import Template
from pycuda.compiler import SourceModule
src_template = Template(
"""
struct Dist {
%for s in xrange(ns):
float *dist${s};
%endfor
};
// return linear index based on x,y coordinate
__device__ int get_index(int xcoord, int ycoord)
{
return ycoord + xcoord * ${ny};
};
__global__ void initialize(float *rho, float *ux, float *uy, Dist *ftmp)
{
int idx;
float dens, velx, vely, vv, ev;
for (int y = threadIdx.x + blockIdx.x * blockDim.x;
y < ${ny};
y += blockDim.x * gridDim.x)
{
for (int x = threadIdx.y + blockIdx.y * blockDim.y;
x < ${nx};
x += blockDim.y * gridDim.y)
{
if ((x > 0) && (x < ${nx-1}) && (y > 0) && (y < ${ny-1}))
{
idx = get_index(x,y);
dens = rho[idx]; velx = ux[idx]; vely = uy[idx];
vv = velx*velx + vely*vely;
%for s in xrange(ns):
// s = ${s}; \vec{e}[${s}] = [${ex[s]},${ey[s]}]
ev = ${float(ex[s])}f*velx + ${float(ey[s])}f*vely;
ftmp->dist${s}[idx] = ${w[s]}f*dens*(1.0f+3.0f*ev+4.5f*ev*ev-1.5f*vv);
%endfor
}
}
}
}
"""
)
class channelFlow:
# initialize channelFlow
def __init__(self, nx, ny):
self.nx, self.ny = nx, ny
max_threads_per_block = tools.DeviceData().max_threads
self.blocksize = (ny if ny<32 else 32, nx if nx<32 else 32, 1) # threads per block
self.gridsize = (ny/self.blocksize[0], nx/self.blocksize[1], 1) # blocks per grid
self.ns = 9
self.w = np.array([4./9, 1./9, 1./9, 1./9, 1./9, 1./36, 1./36, 1./36, 1./36])
self.ex = np.array([0, 1, -1, 0, 0, 1, -1, -1, 1])
self.ey = np.array([0, 0, 0, 1, -1, 1, 1, -1, -1])
self.ctx = { 'nx': self.nx, 'ny': self.ny, 'ns': self.ns,
'w': self.w, 'ex': self.ex, 'ey': self.ey
}
dtype = np.float32
self.ftmp = np.zeros([self.nx,self.ny,self.ns]).astype(dtype)
self.rho = np.zeros([self.nx,self.ny]).astype(dtype)
self.ux = np.zeros([self.nx,self.ny]).astype(dtype)
self.uy = np.zeros([self.nx,self.ny]).astype(dtype)
self.ftmp_gpu = cuda.mem_alloc(self.ftmp.nbytes)
self.rho_gpu = cuda.mem_alloc(self.rho.nbytes)
self.ux_gpu = cuda.mem_alloc(self.ux.nbytes)
self.uy_gpu = cuda.mem_alloc(self.uy.nbytes)
def run(self):
src = src_template.render(**self.ctx)
code = SourceModule(src)
initialize = code.get_function('initialize')
self.rho[:,:] = 1.
self.ux[:,:] = 0.
self.uy[:,:] = 0.
cuda.memcpy_htod(self.rho_gpu, self.rho)
cuda.memcpy_htod(self.ux_gpu, self.ux)
cuda.memcpy_htod(self.uy_gpu, self.uy)
initialize(
self.rho_gpu, self.ux_gpu, self.uy_gpu,
self.ftmp_gpu,
block=self.blocksize, grid=self.gridsize
)
if __name__ == "__main__":
sim = channelFlow(64,64); sim.run()
【问题讨论】：
标签： python c cuda indexoutofboundsexception pycuda