【发布时间】:2016-10-21 16:47:44
【问题描述】:
我正在编写一个 CUDA 内核调度程序。调度程序获取Task 指针向量并将它们带入执行。指针指向不同类型参数的KernelTask 对象,以支持具有任意参数的内核。
调度程序有 CPU 版本和 GPU 版本。 CPU版本工作正常。它调用虚函数Task::start 来执行一个内核。 GPU版本存在三个问题:
- CUDA 中不允许使用虚拟函数。我怎样才能在不向下投射的情况下避免它们?
- std::get 是一个主机函数。有没有办法为 GPU 实现 std::get 自己?
- (低优先级)因为
KernelTask对象的大小不同,所以我用copyToGPU()单独复制所有这些对象。有没有批量复制的方法?
代码如下:
// see http://stackoverflow.com/questions/7858817/unpacking-a-tuple-to-call-a-matching-function-pointer
template<int ...>
struct seq { };
template<int N, int ...S>
struct gens : gens<N-1, N-1, S...> { };
template<int ...S>
struct gens<0, S...> {
typedef seq<S...> type;
};
class Task {
private:
bool visited;
bool reached;
protected:
std::vector<std::shared_ptr<Task>> dependsOn;
Task();
public:
Task **d_dependsOn = NULL;
int d_dependsOnSize;
Task *d_self = NULL;
int streamId;
int id;
cudaStream_t stream;
virtual void copyToGPU() = 0;
virtual void start() = 0;
virtual void d_start() = 0;
virtual ~Task() {}
void init();
void addDependency(std::shared_ptr<Task> t);
cudaStream_t dfs();
};
template<typename... Args>
class KernelTask : public Task {
private:
std::tuple<Args...> params;
dim3 threads;
dim3 blocks;
void (*kfp)(Args...);
template<int ...S>
void callFunc(seq<S...>) {
// inserting task into stream
this->kfp<<<this->blocks, this->threads, 0, this->stream>>>(std::get<S>(params) ...);
checkCudaErrors(cudaGetLastError());
if (DEBUG) printf("Task %d: Inserting Task in Stream.\n", this->id);
}
template<int ...S>
__device__ void d_callFunc(seq<S...>) {
// inserting task into stream
this->kfp<<<this->blocks, this->threads, 0, this->stream>>>(std::get<S>(params) ...);
if (DEBUG) printf("Task %d: Inserting Task in Stream.\n", this->id);
}
KernelTask(int id, void (*kfp)(Args...), std::tuple<Args...> params, dim3 threads, dim3 blocks);
public:
~KernelTask();
void copyToGPU();
void start() override {
callFunc(typename gens<sizeof...(Args)>::type());
}
__device__ void d_start() override {
d_callFunc(typename gens<sizeof...(Args)>::type());
}
static std::shared_ptr<KernelTask<Args...>> create(int id, void (*kfp)(Args...), std::tuple<Args...> params, dim3 threads, dim3 blocks);
};
class Scheduler {
private:
std::vector<std::shared_ptr<Task>> tasks;
public:
Scheduler(std::vector<std::shared_ptr<Task>> &tasks) {
this->tasks = tasks;
}
void runCPUScheduler();
void runGPUScheduler();
};
编辑:
(1) CUDA 中的虚拟函数:在以下示例中,scheduler 出现 Warp Illegal Address 异常:
struct Base {
__host__ __device__ virtual void start() = 0;
virtual ~Base() {}
};
struct Derived : Base {
__host__ __device__ void start() override {
printf("In start\n");
}
};
__global__ void scheduler(Base *c) {
c->start();
}
int main(int argc, char **argv) {
Base *c = new Derived();
Base *d_c;
checkCudaErrors(cudaMalloc(&d_c, sizeof(Derived)));
checkCudaErrors(cudaMemcpy(d_c, c, sizeof(Derived), cudaMemcpyHostToDevice));
c->start();
scheduler<<<1,1>>>(d_c);
checkCudaErrors(cudaFree(d_c));
return 0;
}
(2) thrust::tuple 工作正常。
(3) 我愿意接受建议。
(4) 如何将内核函数指针传递给内核?在以下示例中,我得到了 Warp Misaligned Address 异常:
__global__ void baz(int a, int b) {
printf("%d + %d = %d\n", a, b, a+b);
}
void schedulerHost(void (*kfp)(int, int)) {
kfp<<<1,1>>>(1,2);
}
__global__ void schedulerDevice(void (*kfp)(int, int)) {
kfp<<<1,1>>>(1,2);
}
int main(int argc, char **argv) {
schedulerHost(&baz);
schedulerDevice<<<1,1>>>(&baz);
return 0;
}
【问题讨论】:
-
Virtual functions are not allowed in CUDA。他们是。Is there a way to implement std::get myself。是的,尽管严格来说这是标准不允许的。 -
从任务对象调用 d_start() 时,我收到以下信号:
CUDA_EXCEPTION_14:Warp Illegal Address。你知道如何实现 std::get 吗? -
查看我对内核参数的编辑。