【发布时间】:2017-10-03 23:31:23
【问题描述】:
Program received signal SIGSEGV, Segmentation fault.
memcpy ()
at ../sysdeps/x86_64/multiarch/../multiarch/memmove-vec-unaligned-erms.S:143
143 ../sysdeps/x86_64/multiarch/../multiarch/memmove-vec-unaligned-erms.S: No such file or directory.
(gdb) bt
#0 memcpy ()
at ../sysdeps/x86_64/multiarch/../multiarch/memmove-vec-unaligned-erms.S:143
#1 0x00007ffff764aa2e in __GI__IO_default_xsputn (f=0x7fffffffcf30,
data=<optimized out>, n=30) at genops.c:438
#2 0x00007ffff761c59c in _IO_vfprintf_internal (
s=s@entry=0x7fffffffcf30, format=<optimized out>,
format@entry=0x55555555773f "%s/%s", ap=ap@entry=0x7fffffffd058)
at vfprintf.c:1637
#3 0x00007ffff763e61b in __IO_vsprintf (
string=0x3930313938393339 <error: Cannot access memory at address 0x3930313938393339>, format=0x55555555773f "%s/%s",
args=args@entry=0x7fffffffd058) at iovsprintf.c:42
#4 0x00007ffff7623717 in __sprintf (s=<optimized out>,
format=<optimized out>) at sprintf.c:32
#5 0x000055555555680e in take_action (
hash=0x7fffffffd4d0 "4ef3065e42d1ba6d821e734b2957b264",
index=0x7fffffffd36c, filnamE=0x7fffffffd5d0 "fs",
time_s=0x7fffffffd4a0 "1493989109") at file_sync.c:652
#6 0x0000555555556f25 in run_client (port_no=10009) at file_sync.c:821
#7 0x00005555555571df in main (argc=3, argv=0x7fffffffdef8)
at file_sync.c:923
我得到这个的代码是:
char *fnam;
int nn = sprintf(fnam,"%s/%s",cwd,filnam);
fnam[nn] = '\0';
其中cwd 是一个字符串,其值为:"/home/username/dir1/dir2/di3"
filnam 具有价值:fs
我知道这些是值,因为我已经将它们打印出来了。
有人可以为我解释这个错误吗?我似乎无法弄清楚这一点。请在这件事上给予我帮助!谢谢!
编辑:
好的,这是要求的声明:
char cwd[256];
getcwd(cwd, sizeof(cwd));
**// getting cwd here**
DIR *directory = NULL;
pdir = opendir(cwd);
if(directory == NULL){printf("\nDirectory bad!!\n");exit(1);}
char * filnam;
struct dirent *uppp = NULL;
while( uppp = readdir(directory) )
{
if(uppp == NULL){printf("\nproblemo. \n"); exit(1);}
filnam = uppp->d_name;
if(filnam[0] == '.') { continue; }
**// this is where I'm getting filename**
}
【问题讨论】:
-
我不知道为什么这会被否决
-
Program received signal SIGSEGV, Segmentation fault。看起来这是一个段错误。 -
但是如果你没有正确分配
fnam[],并且超出了内存缓冲区,行为是不确定的。它可能在某些时候有效,然后在其他时候无效。 -
问题的关键在这里
string=0x3930313938393339 <error: Cannot access memory at address 0x3930313938393339>对我来说,这看起来更像是 ASCII 而不是地址:-o -
if(uppp == NULL){printf("\nproblemo. \n"); exit(1);}读起来非常不愉快,而且没有必要,因为由于循环控制,uppp不会在循环内成为NULL。在我看来,您正在仔细检查只是为了确定,这是一件可怕的事情,它表明您不知道自己在做什么。
标签: c memory tcp network-programming printf