如何访问孩子的xml文本？

Question

我有以下 xml 文件（取自 here:

<BioSampleSet>
   <BioSample submission_date="2011-12-01T13:31:02.367" last_update="2014-11-08T01:40:24.717" publication_date="2012-02-16T10:49:52.970" access="public" id="761094" accession="SAMN00761094">
   <Ids>
   </Ids>
   <Package display_name="Generic">Generic.1.0</Package>
   <Attributes>
      <Attribute attribute_name="Individual">PK314</Attribute>
      <Attribute attribute_name="condition">healthy</Attribute>
      <Attribute attribute_name="BioSampleModel">Generic</Attribute>
   </Attributes>
   <Status status="live" when="2014-11-08T00:27:24"/>
   </BioSample>
</BioSampleSet>

而且我需要访问子属性attribute_name 旁边的文本Attributes。 我设法访问了 attribute_name.:

的值

from Bio import Entrez,SeqIO
Entrez.email = '#'
import xml.etree.ElementTree as ET

handle = Entrez.efetch(db="biosample", id="SAMN00761094", retmode="xml", rettype="full")
tree = ET.parse(handle)
for attr in root[0].iter('Attribute'):
    name = attr.get('attribute_name')
    print(name)

打印出来：

Individual
condition
BioSampleModel

如何创建attribute_name 的值的dict 及其旁边的文本？

我想要的输出是

attributes = {'Individual': PK314, 'condition': healthy, 'BioSampleModel': Generic}

Answer 1

严格根据问题中的 xml 示例，尝试以下方式：

bio = """[your xml sample]"""
doc = ET.fromstring(bio)
attributes = {}
for item in doc.findall('.//Attributes//Attribute'):        
    attributes[item.attrib['attribute_name']]=item.text
attributes

输出：

{'Individual': 'PK314', 'condition': 'healthy', 'BioSampleModel': 'Generic'}