MySQL 从表中选择数据并内连接联合从另外两个相同表中的所有选择答案

【问题标题】：MySQL select data from table and inner join the union all selection from another two identical tablesMySQL 从表中选择数据并内连接联合从另外两个相同表中的所有选择
【发布时间】：2015-02-17 06:17:28
【问题描述】：

首先，我有两个表，我使用以下查询进行连接

选择 o5.id 作为 id， DATE_FORMAT(o5.vreme_isplata, '%d.%m.%Y') AS payed_date, o5.ime_prezime AS 名称， o5.adresa AS 地址， o5.mesto AS 城市， o5.embg AS mb， o5.serial_no AS 票证， o1.uplata 作为 uplata， o5.pdd AS danok, o5.isplata AS neto_dobivka, o1.iznos_isplaten AS bruto_dobivka 从 o5 内连接o1 ON o5.serial_no = o1.serial_no WHERE o1.transaction_type = '我'

它的工作正常现在我需要从另一个表“o1_payout_storno”中选择数据，女巫与o1相同我需要从o5 和INNER JOIN 中选择数据，从o1 和o1_payout_storno 中选择UNION ALL。

【问题讨论】：

标签： php mysql join union

【解决方案1】：

应该这样直截了当：

SELECT 
  o5.id AS id, 
  DATE_FORMAT(o5.vreme_isplata, '%d.%m.%Y') AS payed_date, 
  o5.ime_prezime AS name, 
  o5.adresa AS address, 
  o5.mesto AS city, 
  o5.embg AS mb, 
  o5.serial_no AS ticket, 
  o1.uplata AS uplata, 
  o5.pdd AS danok, 
  o5.isplata AS neto_dobivka, 
  o1.iznos_isplaten AS bruto_dobivka 
FROM o5 
INNER JOIN o1 ON o5.serial_no = o1.serial_no 
WHERE o1.transaction_type = 'I' 
UNION ALL
SELECT 
  o5.id AS id, 
  DATE_FORMAT(o5.vreme_isplata, '%d.%m.%Y') AS payed_date, 
  o5.ime_prezime AS name, 
  o5.adresa AS address, 
  o5.mesto AS city, 
  o5.embg AS mb, 
  o5.serial_no AS ticket, 
  op.uplata AS uplata, 
  o5.pdd AS danok, 
  o5.isplata AS neto_dobivka, 
  op.iznos_isplaten AS bruto_dobivka 
FROM o5
INNER JOIN o1_payout_storno AS op ON op.serial_no = o5.serial_no

【讨论】：

感谢您的回答，但在第二次选择中，我需要从 o5 中选择数据，我将尝试使用内部连接 o1 从 o5 中进行选择，然后将所有来自 o5 的选择与内部连接 o1_payout_storno 联合起来

【解决方案2】：

我终于得到了查询

SELECT o5.id AS id, 
DATE_FORMAT(o5.vreme_isplata, '%d.%m.%Y') AS payed_date, 
o5.ime_prezime AS name, 
o5.adresa AS address, 
o5.mesto AS city,
o5.embg AS mb, 
o5.serial_no AS ticket, 
o1.uplata AS uplata, 
o5.pdd AS danok, 
o5.isplata AS neto_dobivka, 
o1.iznos_isplaten AS bruto_dobivka 
FROM o5 
INNER JOIN o1 ON o5.serial_no = o1.serial_no
WHERE o1.transaction_type = 'I' 
UNION ALL 
SELECT o5.id AS id, 
DATE_FORMAT(o5.vreme_isplata, '%d.%m.%Y') AS payed_date,
o5.ime_prezime AS name, 
o5.adresa AS address, 
o5.mesto AS city, 
o5.embg AS mb,
o5.serial_no AS ticket, 
o1_payout_storno.uplata AS uplata, 
o5.pdd AS danok, 
o5.isplata AS neto_dobivka,
o1_payout_storno.iznos_isplaten AS bruto_dobivka 
FROM o5 
INNER JOIN o1_payout_storno ON o5.serial_no = o1_payout_storno.serial_no 
WHERE o1_payout_storno.transaction_type = 'I' 
ORDER BY payed_date ASC

它按我的预期工作！

【讨论】：