【发布时间】:2018-01-15 11:00:28
【问题描述】:
您好,我正在尝试使用性别化程序包在 R 中创建一个饼图。 我指的是来自站点https://www.r-bloggers.com/the-gender-of-big-data/的以下代码:
library(rvest)
library(stringr)
library(dplyr)
library(genderizeR)
library(ggplot2)
library(googleVis)
paste0("http://www.crn.com/slide-shows/data-center/300076704/2015-big-data-
100-business-analytics.htm/pgno/0/", 1:45) %>%
c(., paste0("http://www.crn.com/slide-shows/data-center/300076709/2015-big-
data-100-data-management.htm/pgno/0/",1:30)) %>%
c(., paste0("http://www.crn.com/slide-shows/data-center/300076740/2015-big-
data-100-infrastructure-tools-and-services.htm/pgno/0/",1:25)) -> webpages
results=data.frame()
for(x in webpages)
{
read_html(x) %>% html_nodes("p:nth-child(1)") %>% .[[2]] %>% html_text() ->
Company
read_html(x) %>% html_nodes("p:nth-child(2)") %>% .[[1]] %>% html_text() ->
Executive
results=rbind(results, data.frame(Company, Executive))
}
results=data.frame(lapply(results, as.character), stringsAsFactors=FALSE)
results[74,]=c("Trifacta", "Top Executive: CEO Adam Wilson")
results %>%
mutate(Name=gsub("Top|\bExec\S*|\bCEO\S*|President|Founder|and|Co-
Founder|\:", "", Executive)) %>%
mutate(Name=word(str_trim(Name))) -> results
results %>%
select(Name) %>%
findGivenNames() %>%
filter(probability > 0.9 & count > 15) %>%
as.data.frame() -> data
data %>% group_by(gender) %>% summarize(Total=n()) -> dat
doughnut=gvisPieChart(dat,
options=list(
width=450,
height=450,
legend="{ position: 'bottom', textStyle: {fontSize: 10}}",
chartArea="{left:25,top:50}",
title='TOP 100 BIG DATA COMPANIES 2015
Gender of CEOs',
colors="['red','blue']",
pieHole=0.5),
chartid="doughnut")
plot(doughnut)
它会抛出一个错误,提示找不到 mutate 函数,我已经正确安装了所有软件包。有人可以在这里指导我吗?
或者有人可以分享示例代码以使用 R 和 Sparklyr 创建饼图。 这是我的第一个任务,我只是想理解这个概念。 TIA
【问题讨论】:
-
您能否粘贴您收到的确切错误消息?你能试着用包裹打电话给
mutate吗?像这样:dplyr::mutate(...也许它被你在dplyr之后加载的其他包的另一个mutate函数覆盖了
标签: r apache-spark rstudio sparklyr