【发布时间】:2020-01-29 00:07:43
【问题描述】:
我有一个自定义用户模型如下:
class CustomUser(AbstractUser):
username = None
email = EmailField(verbose_name='email address', max_length=255, unique=True, )
first_name = CharField(verbose_name='First Name', max_length=30, null=True, )
middle_name = CharField(verbose_name='Middle Name', max_length=30, null=True, blank=True, )
last_name = CharField(verbose_name='Last Name', max_length=30, null=True, )
phone_number = CharField(verbose_name='Phone Number', max_length=30, null=True, )
is_partner = BooleanField(default=False, )
is_student = BooleanField(default=False, )
USERNAME_FIELD = 'email'
REQUIRED_FIELDS = []
objects = CustomUserManager()
def __str__(self):
return self.email
如上所示,用户可以是学生,也可以是合作伙伴,他们将负责几个学生并可以访问他们的资产。 合作伙伴模式如下:
class Partner(Model):
user = OneToOneField(CustomUser, on_delete=CASCADE)
partner_name = CharField(max_length=100, )
学生模型如下:
class Student(Model):
user = OneToOneField(CustomUser, on_delete=CASCADE)
student_name = CharField(max_length=100, )
partner = ForeignKey(Partner, on_delete=SET_NULL, null=True)
如图所示,在 Student 模型中,partner 可以为 null。原因是学生可以在没有合作伙伴的情况下直接注册系统,或者他/她可以由合作伙伴注册。学生甚至可以在注册时指定可选的合作伙伴。
我有一个学生视图和 url 模式:
path('student_profile/', student_profile, name='student_profile')
def student_profile(request):
user = request.user
student = get_object_or_404(Student, user=user)
return HttpResponse('The student will do AAAAAA')
我有一个 url 模式和合作伙伴视图:
path('partner_profile/', partner_profile, name='partner_profile')
def partner_profile(request):
user = request.user
partner = get_object_or_404(Partner, user=user)
return HttpResponse('The partner will do some stuff such as updating his/her profile')
有这个 url 模式和视图允许合作伙伴查看他/她的学生列表:
path('partners/<int:partner_pk>/students/', partner_students, name='partner_students')
def partner_students(request):
template_name = 'partners/partner_students.html'
context = {}
partner = get_object_or_404(Partner, user=request.user)
partner_students = Student.objects.filter(partner=partner)
context.update({'partner_students': partner_students})
return render(request, template_name, context)
在模板中,我可以有这个url路径:
path('students/<int:student_pk>/', partner_student_profile, name='partner_student_profile')
{% for student in partner_students %}
<a href="{% url 'partner_student_profile' student_pk=student.pk %}">student.pk</a>
{% endfor %}
我需要以某种方式使用已经编写好的视图,而不是重写视图来处理学生资料。 我想用这个:
def student_profile(request):
user = request.user
student = get_object_or_404(Student, user=user)
return HttpResponse('The student will do some stuff such as updating his/her profile')
我不想写这个:
def partner_student_profile(request, student_pk):
student = Student.objects.get(pk=student_pk)
return HttpResponse('The partner will do AAAAAA for his/her student')
我想重用已经写好的“student_profile”视图
【问题讨论】:
标签: django url view model request