【问题标题】:Ignore case class field in ScalaTest matching忽略ScalaTest匹配中的案例类字段
【发布时间】:2020-05-28 14:13:12
【问题描述】:

假设我有几个字段成员的案例类:

case class User(name: String, ..., createdAt: LocalDateTime)

如何在不考虑 createdAt 字段的情况下检查相等性?

有没有更好的办法:

val expected = User("username", stubDate)
actual shouldBe expected.copy(createdAt = actual.createdAt)

【问题讨论】:

    标签: scala scalatest matcher case-class


    【解决方案1】:

    像这样考虑matchPattern

    import org.scalatest.flatspec.AnyFlatSpec
    import org.scalatest.matchers.should.Matchers
    
    class CaseClassPatternMatchSpec extends AnyFlatSpec with Matchers {
      case class User(name: String, age: Int)
    
      "User" should "be Worf where we ignore the age" in {
        val actual = User("Worf", 30)
        actual should matchPattern { case User("Worf", _) => }
      }
    }
    

    或定义custom equality

    import org.scalactic.Equality
    import org.scalatest.flatspec.AnyFlatSpec
    import org.scalatest.matchers.should.Matchers
    
    class CaseClassPatternMatchSpec extends AnyFlatSpec with Matchers {
      case class User(name: String, age: Int)
      object User {
        implicit val aEq: Equality[User] = (a: User, b: Any) => b match {
          case User(name, _) => a.name == name
          case _ => false
        }
      }
    
      "User" should "be Worf where we ignore the age " in {
        val actual = User("Worf", 30)
        val expected = User("Worf", -11)
        actual should === (expected)
      }
    }
    

    仅注意某些匹配器can use custom equality

    result should equal (3) // can customize equality
    result should === (3)   // can customize equality and enforce type constraints
    result shouldEqual 3    // can customize equality, no parentheses required
    

    【讨论】:

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