【发布时间】:2020-09-23 08:44:01
【问题描述】:
我有一个数据框,我创建为MyData1 的架构,然后我创建了一个列,以便新的数据框遵循MyData2 的架构。现在我想将新数据框作为数据集返回,但出现以下错误:
[info] org.apache.spark.sql.AnalysisException: cannot resolve '`hashed`' given input columns: [id, description];
[info] at org.apache.spark.sql.catalyst.analysis.package$AnalysisErrorAt.failAnalysis(package.scala:42)
[info] at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$$anonfun$checkAnalysis$1$$anonfun$apply$3.applyOrElse(CheckAnalysis.scala:110)
[info] at org.apache.spark.sql.catalyst.analysis.CheckAnalysis$$anonfun$checkAnalysis$1$$anonfun$apply$3.applyOrElse(CheckAnalysis.scala:107)
[info] at org.apache.spark.sql.catalyst.trees.TreeNode$$anonfun$transformUp$1.apply(TreeNode.scala:278)
[info] at org.apache.spark.sql.catalyst.trees.TreeNode$$anonfun$transformUp$1.apply(TreeNode.scala:278)
这是我的代码:
import org.apache.spark.sql.{DataFrame, Dataset}
case class MyData1(id: String, description: String)
case class MyData2(id: String, description: String, hashed: String)
object MyObject {
def read(arg1: String, arg2: String): Dataset[MyData2] {
var df: DataFrame = null
val obj1 = new Matcher("cbutrer383", "e8f8chsdfd")
val obj2 = new Matcher("cbutrer383", "g567g4rwew")
val obj3 = new Matcher("cbutrer383", "567yr45e45")
df = Seq(obj1, obj2, obj3).toDF("id", "description")
df.withColumn("hashed", lit("hash"))
val ds: Dataset[MyData2] = df.as[MyData2]
ds
}
}
我知道下一行可能有问题,但无法弄清楚
val ds: Dataset[MyData2] = df.as[MyData2]
我是新手,所以可能犯了一个基本错误。任何人都可以帮忙吗? TIA
【问题讨论】:
-
你忘记分配
df = df.withColumn(... -
你遇到了什么错误?
-
尽量避免
var和null分配.. 使用Option | Some | None相同
标签: scala apache-spark apache-spark-sql apache-spark-dataset