django rest框架json序列化器

Question

我想要来自 Django REST 框架的 json 响应，所以我有这样的 Json 响应：.

[
    {
        "id": 1,
        "TitleEnglish": "Tiny Talents Program",
        "TitleArabic": "Tiny Talents Program",
        "DescriptionEnglish": "Timing: 8:00 am till 1:00 pm",
        "DescriptionArabic": "Timing: 8:00 am till 1:00 pm",
        "CategoryEnglish": "Art & Education ",
        "CategoryArabic": "Art & Education ",
        "Date": "2015-05-07",
        "Status": true,
        "Image": "--"
    }
]

但我需要这样的回应：

{
"data": [
    {
        "id": 1,
        "TitleEnglish": "Tiny Talents Program",
        "TitleArabic": "Tiny Talents Program",
        "DescriptionEnglish": "Timing: 8:00 am till 1:00 pm",
        "DescriptionArabic": "Timing: 8:00 am till 1:00 pm",
        "CategoryEnglish": "Art & Education ",
        "CategoryArabic": "Art & Education ",
        "Date": "2015-05-07",
        "Status": true,
        "Image": "--"
    }
       ]
}

我的序列化代码是：

class PromotionSerializer(serializers.HyperlinkedModelSerializer):
    CategoryEnglish  = serializers.CharField(read_only=True, source="Category.TitleEnglish")
    CategoryArabic  = serializers.CharField(read_only=True, source="Category.TitleArabic")
    class Meta:
        model = Promotion
        fields = ('id', 'TitleEnglish', 'TitleArabic', 'DescriptionEnglish', 'DescriptionArabic', 'CategoryEnglish','CategoryArabic', 'Date','Status','Image')

Answer 1

我通过更改视图解决了我的问题：

我添加了一个列表方法，我的问题解决了：

def list(self, request):
    queryset = Promotion.objects.all()
    serializer_class = PromotionSerializer(queryset, many=True)
    serialized_data =  {'data': serializer_class.data}
    return Response(serialized_data)

Answer 2

我认为您可以通过自定义 ListSerializer 行为来做到这一点，该行为在为 list 请求创建序列化响应时使用。

我们可以创建一个自定义的PromotionListSerializer，当使用many=Tue 参数将多个实例传递给序列化程序进行序列化时将使用它。

我们覆盖 PromotionListSerializer 类中的 data 属性以返回我们的自定义表示。

class PromotionListSerializer(serializers.ListSerializer):

    @property
    def data(self):
        # call the super() to get the default serialized data
        serialized_data =  super(PromotionListSerializer, self).data       
        custom_representation = {'data': serialized_data} # insert the above response in a dictionary
        return custom_representation

然后在您的PromotionSerializer 中，在Meta 中指定此自定义列表序列化程序类。然后在序列化多个实例时将使用此自定义列表序列化程序类。

class PromotionSerializer(serializers.HyperlinkedModelSerializer):
    CategoryEnglish  = serializers.CharField(read_only=True, source="Category.TitleEnglish")
    CategoryArabic  = serializers.CharField(read_only=True, source="Category.TitleArabic")
    class Meta:
        model = Promotion
        fields = ('id', 'TitleEnglish', 'TitleArabic', 'DescriptionEnglish', 'DescriptionArabic', 'CategoryEnglish','CategoryArabic', 'Date','Status','Image')

        # define the custome list serializer class to be used
        list_serializer_class = PromotionListSerializer

解决方案 2：

覆盖视图的list 方法并返回自定义表示，而不是您在your ans. 中提到的默认响应

扩展OP's 答案，这也将为分页响应提供支持。这是 DRF 中的实际代码，我刚刚返回了 custom_representation 而不是最后的 serializer.data。

def list(self, request, *args, **kwargs):
    instance = self.filter_queryset(self.get_queryset())
    page = self.paginate_queryset(instance)
    if page is not None:
        serializer = self.get_pagination_serializer(page)
    else:
        serializer = self.get_serializer(instance, many=True)
    serialized_data = serializer.data
    custom_representation = {'data': serialized_data}
    return Response(custom_representation)

Answer 3

最简单的解决方案是覆盖 to_representation 方法

def to_representation(self, instance):
    data = super(PromotionSerializer, self).to_representation(instance)
    return {'data': data }