【发布时间】:2019-12-05 13:03:55
【问题描述】:
我正在开发一个必须将用户数据发布到数据库的应用程序(登录名、密码、设备 ID、纬度和经度)。我正在尝试通过 PHP 发布它,但我收到错误 "End of input at line 1 column 1 path $".
我不确定我应该怎么做。
我试图用 gson 做一些事情,但它也不起作用。如果有人有任何想法,请告诉我... :)
这是我的 MainActivity 代码:
public void createPost(String loginStr, String passwordStr, String id_urzadzenia, double latitude, double longitude) throws IOException {
Gson gson = new GsonBuilder()
.setLenient()
.create();
Retrofit retrofit = new Retrofit.Builder()
.baseUrl("https://unpreached-courtesy.000webhostapp.com")
.addConverterFactory(GsonConverterFactory.create(gson))
.build();
API ApiPlaceHolder = retrofit.create(API.class);
Call<Post> call = ApiPlaceHolder
.createPost(
loginStr,
passwordStr,
id_urzadzenia,
latitude,
longitude);
call.enqueue(new Callback<Post>() {
@Override
public void onResponse(Call<Post> call, Response<Post> response) {
if (!response.isSuccessful()) {
Toast.makeText(MainActivity.this, "Code " + response.code(), Toast.LENGTH_SHORT).show();
}
}
@Override
public void onFailure(Call<Post> call, Throwable t) {
Toast.makeText(MainActivity.this, t.getMessage(), Toast.LENGTH_LONG).show();
Toast.makeText(MainActivity.this, call.request().toString(), Toast.LENGTH_SHORT).show();
}
});
}
API接口代码:
public interface API {
@FormUrlEncoded
@POST("/dane.php")
Call<Post> createPost (
@Field("loginStr")String loginStr,
@Field("passwordStr") String passwordStr,
@Field("id_urzadzenia") String id_urzadzenia,
@Field("latitude") double latitude,
@Field("longitude") double longitude
);
}
Post.java 类代码:
public class Post {
private String loginStr;
private String passwordStr;
private String id_urzadzenia;
private double latitude;
private double longitude;
public String getLoginStr() {
return loginStr;
}
public void setLoginStr(String loginStr) {
this.loginStr = loginStr;
}
public String getPasswordStr() {
return passwordStr;
}
public void setPasswordStr(String passwordStr) {
this.passwordStr = passwordStr;
}
public String getId_urzadzenia() {
return id_urzadzenia;
}
public void setId_urzadzenia(String id_urzadzenia) {
this.id_urzadzenia = id_urzadzenia;
}
public double getLatitude() {
return latitude;
}
public void setLatitude(double latitude) {
this.latitude = latitude;
}
public double getLongitude() {
return longitude;
}
public void setLongitude(double longitude) {
this.longitude = longitude;
}
}
还有我的 PHP:
<?php header('Content-Type: application/json');
$con = mysqli_connect(DB_SERVER,DB_USER,DB_PASSWORD,DB_DATABASE);
$login = $_POST["loginStr"];
$id_urz = $_POST["id_urzadzenia"];
$dl_geo = $_POST["longitude"];
$sz_geo = $_POST["latitude"];
echo "Login użytkownika: " .$login . "\n";
echo "ID urządzenia: " . $id_urz . "\n";
echo "Szerokość geograficzna: " . $sz_geo . "\n";
echo "Długość geograficzna: " . $dl_geo . "\n";
date_default_timezone_get(Europe);
$godz = date("H:i:s");
$sql = "INSERT INTO TABLE bartek (id_urzadzenia,szerokosc,dlugosc,data) VALUES ('".json_encode($id_urz)."','".json_encode($sz_geo)."','".json_encode($dl_geo)."','".$godz."'";
mysqli_query($con, $sql);
mysqli_close($con);
?>
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